1. The problem statement, all variables and given/known data Find the speed, v, which an electron, emitted with kinetic energy W = 0.200 eV, arrives at the anode when the accelerating voltage between the anode and the cathode is U = 2.00 V. b) The value I of the photoelectric current 2. Relevant equations From what i gather, Etotal = Ekinetic + work function = qV + work function 3. The attempt at a solution Im not sure if the first question is poorly worded or I'm just misunderstanding it, but I assume by 'kinetic energy W = 0.200' they mean the work function. I solved it like so Etotal = Ekinetic + work function = qV + work function ETOT = ((1.6x10-19)x(2) + (0.2 x 1.6x10-19) = 3.52x10-19 joules 3.52x10-19 = 1/2 mv2, solving for v i get 879077m/s. Does the electron actually move 879 KILOMETERS a second? Wow. Is this right? Is it true only because it travels a very short distance in total, over a short time? I'm having a hard time conceptualizing this. Now for b I'm really not sure how to approach this, I know current I = voltage / resistance, but it's not applicable in this situation, from the last question we know that the voltage is (3.52x10-19)/(1.6x10-19) which seems to be 2.2 volts? But where do I go from here? If possible I need urgent clarification, I need to go sleep soon. Thanks for any help!