Checking Speed/Velocity Porblem Answers

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AI Thread Summary
The discussion revolves around two physics problems involving speed and velocity. For the first problem, the average speed of the dog is confirmed as 10 ft/s, but the average velocity was initially miscalculated; the correct average velocity is 3.5 ft/s after correcting the time calculation. In the second problem, the time for two cars traveling towards each other at 60 mph to meet is correctly identified as 6 minutes. Participants clarify the importance of correctly applying time in calculations, leading to a better understanding of average velocity. Overall, the thread emphasizes the need for careful consideration of both distance and time in physics problems.
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Homework Statement



I have two problems.

1. Your dog is sent to fetch the newspaper in the morning. He runs directly away from you,traveling 62.0 feet in 5.0 seconds. He then turns around and in 4.0 seconds runs 30 feet back toward you before deciding to stop. Calculate the dog's average speed and average velocity.

2. Two cars are traveling 12 miles apart and are approaching each other on a straight road. Each car is moving at 60 million/h relative to the road. How long will it take before the cars pass each other? Give your answer in minutes.

Homework Equations





The Attempt at a Solution


I am pretty sure of my answers, but would like to check them before turning them in.
1. Speed: 10 ft/s Velocity: 32 ft/s

2. 6 minutes.


Thanks in advance!
 
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Medgirl314 said:
1. Speed: 10 ft/s Velocity: 32 ft/s
The speed is about right (don't know how many significant figures are required), but for the velocity you appear to have forgotten to do something.
The time in q2 is right.
 
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Thank you! Do you have an idea of what I may have forgotten? For the velocity I subtracted 30 ft. from 60 ft. and then divided by 5 seconds minus four seconds, yielding 32 ft. over 1 second, yielding my answer of 32 ft./s
 
Medgirl314 said:
Thank you! Do you have an idea of what I may have forgotten? For the velocity I subtracted 30 ft. from 60 ft. and then divided by 5 seconds minus four seconds, yielding 32 ft. over 1 second, yielding my answer of 32 ft./s
Why did you subtract 4 seconds from 5 seconds? Did time run backwards?
 
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Oh! Thank you! I assumed that since I subtracted in the numerator I should subtract in the denominator, but I wasn't thinking critically. So I would actually add 4 and 5, yielding an average velocity of 3.5 ft/s.
 
Medgirl314 said:
Oh! Thank you! I assumed that since I subtracted in the numerator I should subtract in the denominator, but I wasn't thinking critically. So I would actually add 4 and 5, yielding an average velocity of 3.5 ft/s.
Much better.
 
Thank you! That was the one answer that seemed off.
 
Wow. I can't believe I misspelled "problems" in this. I should drink more coffee before attempting physics tomorrow.
 
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