Chemical Potential in a Degenerate Fermi Gas

Click For Summary

Homework Help Overview

The discussion revolves around the chemical potential in a degenerate Fermi gas, particularly focusing on its behavior at low and high temperatures in relation to the Fermi energy.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants explore the relationship between chemical potential and Fermi energy, questioning how the chemical potential behaves as temperature increases. There are attempts to connect the behavior of the chemical potential to that of an ideal gas at high temperatures.

Discussion Status

Some participants have provided references to literature for derivations related to the chemical potential, while others are exploring the implications of temperature changes on the chemical potential. Multiple interpretations of the chemical potential's behavior are being discussed, particularly in the context of different temperature regimes.

Contextual Notes

There is mention of specific conditions under which the chemical potential is considered, such as the assumption of low temperatures compared to the Fermi energy and the transition to classical gas behavior at high temperatures.

indigojoker
Messages
240
Reaction score
0
in a Fermi gas, we know that when the temperature is much less than the Fermi energy, it becomes a degenerate gas. does this mean the chemical potential of the system be very large?
 
Physics news on Phys.org
the chemical potential is very close to the fermi energy since the temperature is very much less than the fermi energy
<br /> \mu \approx E_{\rm Fermi}(1 - O((T/E_{\rm Fermi})^2)<br />
 
where did you get the formula for the chemical potential?

So the chemical potential becomes a large negative number as temperature increases? I am trying to show that at high temperatures, the chemical potential is the same as an ideal gas.

(i am considering the 2-d case)
 
Last edited:
that formula is for T << E_F
which is always the case for a metal (since all metals melt well before T=E_F)...

it is derived, for example, in Ashcroft and Mermin "Solid State Physics" chapter 2. See, Eq. 2.77.
For the 2d case see A+M chapter 2 problem number 1. for the classical limit see A+M chapter 2 problem 3.
 
what happens to the chemical potential as T increases to T>E_F?
 
for high temperatures the system will be a gas. if the temperature is high enough it will be a classical gas for which the Boltzmann distribution will hold--i.e., for either fermions or bosons the mean occupation number is very low and proportional to
<br /> e^{-(E-\mu)/T}<br />
which can result from the fermi (bose) distribution
<br /> \frac{1}{e^{(E-\mu)/T}\pm 1}<br />
if \mu is negative and large in magnitude. I.e., e^{|\mu|/T}&gt;&gt;1.
 
Indigojoker: as far as I know, there is no analytic expression for the chemical potential of a non-interacting fermi gas. I remember doing this derivation at some point, and I think I went via the canonical partition function: F=kT ln Z, and \mu=dF/dN. It's not possible to evaluate the expression directly, but you should be able to show that in the high T limit it would tend to the same form as the ideal gas.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K