Chemistry Molar solubility lab questions

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SUMMARY

The discussion clarifies the distinction between molar solubility and the solubility product constant (Ksp) specifically for calcium hydroxide (Ca(OH)2). Molar solubility refers to the concentration of dissolved Ca(OH)2 in equilibrium with excess solid, while Ksp remains constant under specific conditions, although solubility can change with the addition of acids. The conversation emphasizes the importance of knowing Ksp or measured solubility for accurate calculations, particularly in experimental contexts such as titration.

PREREQUISITES
  • Understanding of molar solubility and Ksp concepts
  • Familiarity with calcium hydroxide (Ca(OH)2) properties
  • Knowledge of chemical equilibrium principles
  • Experience with titration techniques in laboratory settings
NEXT STEPS
  • Research the calculation methods for molar solubility from Ksp values
  • Study the effects of pH on the solubility of Ca(OH)2
  • Learn about the hygroscopic nature of Ca(OH)2 and its implications for laboratory use
  • Explore titration methods for determining solubility in experimental chemistry
USEFUL FOR

Chemistry students, laboratory technicians, and educators seeking to deepen their understanding of solubility concepts and practical applications in chemical analysis.

Madelin Pierce
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Homework Statement
Calculate molar solubility of Ca(OH)2, concentrations of Ca^2+ and OH^-, and Ksp
Relevant Equations
Ksp= s(2s)^2, Ksp= [Ca^2+][OH^-]^2
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I’m confused on how to calculate molar solubility because I don’t see what’s the difference between that and Ksp.
 
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The solubility of Ca(OH)2 means just number of moles per litre of Ca(OH)2 (equal also to [Ca2+] ) in solution when you mix an excess of solid calcium hydroxide with water and allow it to come to equilibrium, that is allowed all that is ever going to dissolve to do so. (At that temperature).

That refers to calcium hydroxide by itself with water. If you add acid more will dissolve. Because you are removing OH- so displacing an equilibrium. So you could say the solubility of calcium hydroxide changes when you add acid. On the other hand the solubility constant, which is defined in your second equation, is constant, doesn't change according to these circumstances. (It does change with the temperature).

If you knew the solubility constant Ksp you could calculate the solubility from the very broad hint in your first equation. That would be a purely theoretical calculation. (.But now I have reminded you of the difference between solubility and solubility product, you will probably find it better explained in your textbook)

However it looks as if you are trying to calculate something from experimental measurements. I have to guess what this is about, maybe just you have tou determine the total amount of Ca(OH)2 by titration because if I remember it is hygroscopic and not a very good primary standard, so unreliable to do it by weighing? Anyway to calculate anything you would have to either know the Ksp or a measured solubility - it is not very clear to me what the question is.

.
 
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