Chemistry: Prediction of producs

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Discussion Overview

The discussion revolves around predicting the products of chemical reactions involving various compounds, specifically sodium nitrate, ammonium sulfate, iron (III) acetate, and combinations of sodium phosphate, rubidium chlorate, and strontium nitrate. Participants explore the concepts of solubility, spectator ions, and precipitation in the context of these reactions.

Discussion Character

  • Homework-related
  • Exploratory
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about identifying spectator ions and predicting products, suggesting that iron and sulfide may form a precipitate.
  • Another participant questions whether sulfate or sulfide is involved, suggesting that sulfide precipitation could be a viable approach.
  • A later reply clarifies that sulfate is the correct term, indicating a mix-up in terminology.
  • One participant proposes a reaction involving sodium nitrate, ammonium sulfate, and iron (III) acetate, leading to iron (III) sulfate as a product, while noting that ammonium acetate would be a spectator ion.
  • Another participant argues that iron (III) sulfide is insoluble, implying that no reaction occurs if sulfate is soluble.
  • Discussion on the second question leads to the assumption that strontium phosphate is the insoluble salt formed, based on the solubility rules for phosphates and strontium ions.
  • One participant emphasizes that phosphates exist as PO4^3- and cannot be considered insoluble without a counterion.

Areas of Agreement / Disagreement

Participants express differing views on the solubility of certain compounds and the identification of spectator ions. There is no consensus on the predicted products or the approach to solving the problems presented.

Contextual Notes

Participants reference solubility rules and the nature of ions involved, but there are unresolved assumptions regarding the definitions of solubility and the conditions under which reactions occur.

markelmarcel
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Homework Statement


Predict products (and then write formula unit, total ionic unit & net ionic equations)1. Sodium Nitrate, Ammonium sulfate and Iron (III) acetate.

2. Na3PO4 + RbClO3 + Sr(NO3)2

Homework Equations



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The Attempt at a Solution



1. NaNO3 + (NH4)2S + Fe(CH3CO2)3
I just don't know how to decide what parts will be "spectator ions" and how the 3 products will work out... I know it deals with acids and bases, but my prof went through it really fast and I tried reading our textbook but it didn't help very much with the 3 reactants, and he went out of town for a conference so I couldn't ask him for help...

I think that Fe and S will come together to make a precipitate which would be Fe2S3 and then I'm assuming that the NH4CH3CO2 would then combine together, leaving the NaNO3 as the spectator ions?
 
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Sulfate or sulfide? Sulfide precipitation is a good idea. Similar approach will work for the second question - just think, what combination of ions will produce something insoluble. And don't overdo - ammonium acetate will be just a spectator.

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methods
 
Borek said:
Sulfate or sulfide? Sulfide precipitation is a good idea.


ah, touche! it is sulfate- don't know why when i typed it out i made it into sulfide. i was doing my own chemistry ;)
 
Ok so for the first one I got...

NaNO3 + 3(NH4)2SO4 + 2Fe(CH3CO2)3 \rightarrow Fe2(SO4)3 [/SUB](s) + 6NH4CH3CO2

When I looked up what I had for my solubility rules I found
Na3PO4, RbClO3 and Sr(NO3)2 to all be soluble... So where do I go from here? Randomly place things together??
 
Iron (III) sulfide is insoluble, but sulfate is soluble. No reaction if you ask me.

In the second question one of the combinations of cation and anion give insoluble salt.

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methods
 
Ok I'm still working on balancing but for the second I'm assuming the insoluble salt has to be Sr3(PO4)2

Because PO4 is insoluble, as is Sr (with it being a group II cation).
 
markelmarcel said:
Ok I'm still working on balancing but for the second I'm assuming the insoluble salt has to be Sr3(PO4)2

Like calcium and barium phosphates and sulfates.

Because PO4 is insoluble, as is Sr (with it being a group II cation).

No such thing as insoluble PO4 - it is PO43- and it never exists without counterion.

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