Circluar Motion Involving Rotations Per Minute

  • Thread starter fishyfish
  • Start date
  • #1
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Homework Statement



What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 40 rpm (revolutions per minute) if the wheel's diameter is 35 cm?

Homework Equations



v=2(pi)(r)/t a=(v^2)/r

The Attempt at a Solution



2(3.14)(.175)/.67 = 1.099

(1.099^2)/.175=a
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
3,090
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Welcome to PF.

Isn't your period 1.5 instead of .67?

You only get 40 revs per min so a rev should be longer than a sec no?
 

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