Engineering Circuit Analysis Homework Help: Parts A & C

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SUMMARY

This discussion focuses on solving parts A and C of a circuit analysis homework problem involving an operational amplifier (op-amp) and a bipolar junction transistor (BJT). The voltage at Va is confirmed to be 4V, leading to the conclusion that Vin is also 4V due to the properties of negative feedback in op-amps. The participant is guided to apply Ohm's Law to find the current I1, with a calculated voltage drop of 2V across resistor R1 resulting in a current of 2mA. Nodal analysis is deemed unnecessary as the node voltages are already provided.

PREREQUISITES
  • Understanding of operational amplifier characteristics and negative feedback
  • Knowledge of Ohm's Law for calculating current and voltage
  • Familiarity with bipolar junction transistors (BJTs) and their operation
  • Basic circuit analysis techniques, including nodal analysis
NEXT STEPS
  • Study the principles of operational amplifier analysis, focusing on the two golden rules
  • Learn advanced applications of Ohm's Law in circuit analysis
  • Explore the behavior of BJTs in various configurations and their impact on circuit performance
  • Review nodal analysis techniques for solving complex circuits with multiple nodes
USEFUL FOR

Students and educators in electrical engineering, particularly those studying circuit analysis and operational amplifier applications. This discussion is beneficial for anyone seeking to enhance their understanding of circuit behavior and analysis techniques.

KTiaam
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Homework Statement


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Need help on part a.
and c.

The Attempt at a Solution


  • Part A
Since Va = 4V then pin 2 and 3 also have 4v. Would that mean that Vin is = 4v as well?
Im just confused how to find I1.
Also I am not sure how to find Vc.
  • Part C
As for part c, I am having trouble with it entirely.

Any help is appreciated!
 
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KTiaam said:
Since Va = 4V then pin 2 and 3 also have 4v. Would that mean that Vin is = 4v as well?
Well, yes, but you'll have to argue that based on the characteristics of an opamp with negative feedback. If you think in terms of the two golden rules of ideal opamp analysis..

KTiaam said:
Im just confused how to find I1.
You know what the voltage is across R1. What about Ohm's law?

KTiaam said:
As for part c, I am having trouble with it entirely.
Consider again the behavior of an ideal opamp with the feedback shown. It desperately wants to turn on that BJT hard, so it can reduce the voltage across its terminals to zero, but that really only requires the BJT to just barely move out of its cutoff region. You usually assume something about VBE then.
 
Last edited:
milesyoung said:
You know what the voltage is across R1. What about Ohm's law?

The thing that threw me off, is what voltage to use with r1,
But based off of the orientation of the current source, I use Vb?
 
KTiaam said:
The thing that threw me off, is what voltage to use with r1,
But based off of the orientation of the current source, I use Vb?
The voltage (with respect to ground) at Vb is 6 V, and you drop down to 4 V as you cross the resistor to Va.

Does that help?
 
milesyoung said:
The voltage (with respect to ground) at Vb is 6 V, and you drop down to 4 V as you cross the resistor to Va.

Does that help?
so that means the voltage drop across the resistor is 2v, then using V=IR
i get 2mA?

or do i use Nodal Analysis?
 
KTiaam said:
so that means the voltage drop across the resistor is 2v, then using V=IR
i get 2mA?
Yes. :smile:

Since Vb is at a higher potential than Va, what does that tell you about the direction of the current?

KTiaam said:
or do i use Nodal Analysis?
Nodal analysis is useful when you need to solve for unknown node voltages, but you're already given the node voltages on either side of the resistor, so all there's left to do is just apply Ohm's law.
 
milesyoung said:
Yes. :smile:

Since Vb is at a higher potential than Va, what does that tell you about the direction of the current?

Current goes from a high to low potential so it goes from right to left!

Thank you for all the help Miles! I might have more questions incoming lol.
 

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