Circular Helix Line Integral: Solving with r and dr/dλ

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SUMMARY

The discussion focuses on solving the line integral of the circular helix defined by the parametric equation \(\underline{r} = (a \cos(\lambda), a \sin(\lambda), b\lambda)\) from the point (a, 0, 0) to (a, 0, 2πb). The user is attempting to parameterize the integral as \((\underline{r} \times \frac{d\underline{r}}{d\lambda}) d\lambda\), where \(\frac{d\underline{r}}{d\lambda}\) is the derivative of the helix. Clarification is sought on whether the \(\underline{r}\) in the integral corresponds to the same vector describing the helix.

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ferret123
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Homework Statement



don't know the line integral latex code but;

\int\underline{r}\timesd\underline{r}

from (a,0,0) to (a,0,2∏b) on the circular helix \underline{r} = (acos(λ), asin(λ), bλ)

The Attempt at a Solution



Its the multiple use of the position vector r in the question that's confusing me. So far I've tried paramaterising the original integral as (r cross dr/dλ)dλ with dr/dλ being the derivative of the circular helix however I am confused as to whether the r in the integral is the same as the one describing the helix.

Am I on the right track or will i need to use another method?
 
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ferret123 said:

Homework Statement



don't know the line integral latex code but;

\int\underline{r}\timesd\underline{r}

from (a,0,0) to (a,0,2∏b) on the circular helix \underline{r} = (acos(λ), asin(λ), bλ)

The Attempt at a Solution



Its the multiple use of the position vector r in the question that's confusing me. So far I've tried paramaterising the original integral as (r cross dr/dλ)dλ with dr/dλ being the derivative of the circular helix however I am confused as to whether the r in the integral is the same as the one describing the helix.

Am I on the right track or will i need to use another method?

The r given to you is the parametric representation of the helix. It is easy to check that this is a suitable parametrisation.
 

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