Circular Motion and human blood

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SUMMARY

The discussion focuses on calculating the distance of a blood sample from the rotation axis of a centrifuge operating at 3480 rpm, with an acceleration of 2000g. The user initially attempted to apply the equation ac=V²/r but was advised to use a=ω²*r for clarity. The conversion of frequency to angular velocity (ω) is crucial for accurate calculations. Effective centrifugation requires maintaining an acceleration of at least 2000g to separate blood components efficiently.

PREREQUISITES
  • Understanding of circular motion equations, specifically a=ω²*r
  • Knowledge of angular velocity conversion from rpm to radians per second
  • Familiarity with the concept of centripetal acceleration
  • Basic principles of centrifugation in blood separation
NEXT STEPS
  • Learn how to convert rpm to angular velocity (ω) for centrifuge calculations
  • Study the principles of centrifugation and its applications in laboratory settings
  • Explore the effects of different angles of inclination on centrifugation efficiency
  • Investigate the physical properties of blood components relevant to centrifugation
USEFUL FOR

Students in physics, laboratory technicians, and professionals involved in hematology or biomedical research who require an understanding of centrifugation processes and calculations related to circular motion.

dragonladies1
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For this problem, I tried using the equation:
ac=V2/r and put in

2000= ((2*pi*r)/(1/58))2*r

What is the distance of a sample of blood from the rotation axis of a centrifuge rotating at a frequency f = 3480 rpm, if it has an acceleration of 2000g?
 
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dragonladies1 said:
For this problem, I tried using the equation:
ac=V2/r and put in

2000= ((2*pi*r)/(1/58))2*r

What is the distance of a sample of blood from the rotation axis of a centrifuge rotating at a frequency f = 3480 rpm, if it has an acceleration of 2000g?

I'm not understanding your equation (made harder to understand because no units are shown).

Use a = omega^2 * r instead (close to the form of your equation anyway), and carefully convert 3480rpm into the omega (show the units in your conversion to check yourself).
 
Human blood contains plasma, platelets, and blood cells. To separate the plasma from other components, centrifugation is used. Effective centrifugation requires subjecting blood to an acceleration of 2000g or more. In this situation, assume that blood is contained in test tubes of length L = 14.3 cm that are full of blood. These tubes ride in the centrifuge tilted at an angle of 45.0° above the horizontal (see figure below)

(a) What is the distance of a sample of blood from the rotation axis of a centrifuge rotating at a frequency f = 3480 rpm, if it has an acceleration of 2000g?
cm
(b) If the blood at the center of the tubes revolves around the rotation axis at the radius calculated in Part (a), calculate the accelerations experienced by the blood at each end of the test tube. Express all accelerations as multiples of g.
minimum acceleration g
maximum acceleration g

This is the entire problem.

So for the first part:
a=omega^2*r
a= (2*pi*r/(1/58))^2*r

What am I doing incorrectly?
 

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