Circular Motion Problem -- Ball on a String Spinning in a Vertical Circle

Click For Summary
The discussion revolves around a circular motion problem involving a ball on a string spinning in a vertical circle. The user derives the equation relating velocity and angular velocity but struggles with the two unknowns in the equation. They highlight the importance of understanding the minimum velocity needed for the string to remain taut at the top of the circle. Key considerations include the forces acting on the ball and the conditions required for maintaining tension in the string. The conversation emphasizes the need to analyze the forces at the top of the vertical circle to solve for the unknowns effectively.
Al-Layth
Messages
21
Reaction score
4
Homework Statement
A ball of 5.0 kg mass is attached to the end of a long wire and whirled around in a perfect
circle of 0.9 m radius in the vertical plane. Calculate the following:

Calculate the Minimum Velocity and Minimum Angular Velocity
Relevant Equations
#F= m\frac{v^2}{r} = mw^{2}r#

#m: Mass#
#v: Speed#
#r: Circle Radius#
#w: Angular Velocity#
#F= m\frac{v^2}{r} = mw^{2}r#

#m=5#
#r=0.9#

#F= 5\frac{v^2}{0.9} = (0.9)5w^{2}#

#5\frac{v^2}{0.9} = (0.9)5w^{2}#

#\frac{v^2}{0.9} = (0.9)w^{2}#

#v=0.9w#

then I get stuck cause I have both unknowns in one equations (i bet it has something to do with the question’s use of “minimum” but I don’t know where to go from here) so help mee thx
 
Physics news on Phys.org
The question says the circle is in the vertical plane. What else do you have to take account of in this case?
 
Where is the velocity minimal? What is required for the string to be taut there?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
6
Views
4K
Replies
4
Views
2K
Replies
11
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K