Circular Motion Problem -- Ball on a String Spinning in a Vertical Circle

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The discussion revolves around a circular motion problem involving a ball on a string spinning in a vertical circle. The user derives the equation relating velocity and angular velocity but struggles with the two unknowns in the equation. They highlight the importance of understanding the minimum velocity needed for the string to remain taut at the top of the circle. Key considerations include the forces acting on the ball and the conditions required for maintaining tension in the string. The conversation emphasizes the need to analyze the forces at the top of the vertical circle to solve for the unknowns effectively.
Al-Layth
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Homework Statement
A ball of 5.0 kg mass is attached to the end of a long wire and whirled around in a perfect
circle of 0.9 m radius in the vertical plane. Calculate the following:

Calculate the Minimum Velocity and Minimum Angular Velocity
Relevant Equations
#F= m\frac{v^2}{r} = mw^{2}r#

#m: Mass#
#v: Speed#
#r: Circle Radius#
#w: Angular Velocity#
#F= m\frac{v^2}{r} = mw^{2}r#

#m=5#
#r=0.9#

#F= 5\frac{v^2}{0.9} = (0.9)5w^{2}#

#5\frac{v^2}{0.9} = (0.9)5w^{2}#

#\frac{v^2}{0.9} = (0.9)w^{2}#

#v=0.9w#

then I get stuck cause I have both unknowns in one equations (i bet it has something to do with the question’s use of “minimum” but I don’t know where to go from here) so help mee thx
 
Physics news on Phys.org
The question says the circle is in the vertical plane. What else do you have to take account of in this case?
 
Where is the velocity minimal? What is required for the string to be taut there?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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