Determining Speed of Toy at Top of Loop-the-Loop

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SUMMARY

The discussion centers on calculating the minimum speed required for a toy car with a mass of 100g to maintain contact with the track at the top of a loop-the-loop with a diameter of 0.5m. At this point, the normal force (Fn) approaches zero, meaning the gravitational force (Fg) must provide the necessary centripetal force to keep the car on the track. The key conclusion is that the car must reach a specific speed at the top of the loop to avoid falling off, which can be derived from the principles of circular motion and gravitational force.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Basic knowledge of forces, specifically gravitational and normal forces
  • Familiarity with Newton's laws of motion
  • Ability to apply formulas related to centripetal acceleration
NEXT STEPS
  • Calculate the centripetal acceleration required for the toy car at the top of the loop
  • Explore the relationship between mass, gravitational force, and normal force in circular motion
  • Investigate the concept of critical speed in loop-the-loop scenarios
  • Learn about energy conservation principles in roller coaster physics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of circular motion and forces in real-world applications.

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Homework Statement




A toy with a mass of 100g is going through a loop-the-loop with a diameter of .5m. How fast must the car be moving at the top of the loop in order to not fall.




The Attempt at a Solution



At the top of the loop, there is a normal force (Fn) and the force of gravity (Fg). I'm not sure how to do this. Do I neglect one of the forces? Set one to zero, or what?
 
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What happens to the normal force when the car is just about to lose contact with the track?
 
Fn approaches 0. Thanks.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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