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Circular polarization phase difference

  1. Sep 30, 2014 #1
    Phase difference between two component of Electric field vector seems to me that the phase difference for circular should be of odd multiples of 90 but its not 90 when n value substituted. Please help for solution.. upload_2014-9-30_14-52-12.png
     
  2. jcsd
  3. Sep 30, 2014 #2

    A.T.

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    Which n value did you substitute?
     
  4. Sep 30, 2014 #3
    my doubt is.... as per the textbook i am referring there should be multiples of 90 degree of phase difference is required for circular polarization but here even after substituting all possible values of n= 0,1,2,3,..... I couldn't get multiple of 90... then how can it be the representation of circular polarization phase difference??
     
  5. Sep 30, 2014 #4

    A.T.

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    You do realize that 90° = ## \pi ## / 2 ?
     
  6. Sep 30, 2014 #5
    it is +90 deg = +pi/2 for CW=clockwise and
    -90deg = -pi/2 for CCW= counter clockwise.

    -90 + 360 = 270 = 3*90, so yes, it is odd multiples of 90deg as long as you don't care if it is left-handed or right-handed circular polarization.
     
  7. Oct 1, 2014 #6
    i got it... I was doing silly mistake substituting wrong value...
    Thanks..
     
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