Circular ring in xy-plane with current, find current density

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SUMMARY

The discussion focuses on deriving the expression for current density J in a circular ring of wire with radius a, positioned in the x-y plane. The current density is expressed as J(r) = I₀ * δ(x) * δ(y) * z, indicating that it is non-zero only at z = 0. The transformation to cylindrical coordinates (ρ, θ, z) reveals that J is non-zero at ρ = R and θ = π/2, necessitating the inclusion of delta functions and a normalization factor of 1/R to ensure proper units for current density.

PREREQUISITES
  • Understanding of delta functions in physics
  • Familiarity with cylindrical coordinates (ρ, θ, z)
  • Knowledge of current density concepts in electromagnetism
  • Proficiency in applying Ampère's Law and related equations
NEXT STEPS
  • Study the derivation of current density in different geometries
  • Learn about the applications of delta functions in electromagnetism
  • Explore the implications of current density in cylindrical coordinates
  • Investigate the normalization factors in physical equations
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Students and professionals in physics, particularly those studying electromagnetism and current density in various geometrical configurations.

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Homework Statement


Consider a circular ring of wire of radius a that resides in the x-y plane through the origin. The center of the ring coincides with the origin and you can regard the thickness of the wire to be infinitesimal.

a. Given that a current I flows in the ring, find an expression for the current density J.


Homework Equations



∫B(r).dl = μ∫J(r).da

The Attempt at a Solution



ok, I know J(r)=Io * δ(x)*δ(y) z
How do I get this in cylindrical coordinates (ρ,θ,z)?
 
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Well, the current density is only non-zero at z = 0, that corresponds to it being non-zero only at θ = π / 2, or cos(θ) = 0. So you should have a delta function for that. Additionally, it's non-zero only at ρ = R, so you should have a delta function for that as well. If I remember Jackson correctly, you'll also need a normalization factor of 1/R because θ (and therefore the first delta function) is a dimensionless quantity, so you divide by 1/R to maintain the proper units for current density of current / area (I'm not really sure why this works, I just took Jackson at his word on this one). The original delta functions are functions of position coordinates and therefore already have 1/L dependence.
 

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