1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Classical physics (phase diagram

  1. Jun 22, 2011 #1
    A ball of mass m rests at times t less than 0, at height h above the ground. at time t=0 the ball is released and fell on the ground after hitting the ground, the ball rests there.

    a) x represents distance from the ground, drive and expression for the phase diagram when the ball moving toward the ground. and draw it and find where v and x meet the axis's.



    The attempt at a solution

    1/2(mv^2)= mg(h-x)

    v=sqrt(2g(h-x)) #

    the graph will be a curve (square root) the start will be when x=h and then when it hits the ground will have max v so the position will be zero and v is max.

    Thanks
     
    Last edited: Jun 22, 2011
  2. jcsd
  3. Jun 22, 2011 #2

    cepheid

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    It all seems fine to me. The question asks you for the point at which the curve meets the two axes (plural of axis by the way), in other words it asks for the the x-intercept and v-intercept. So you might want to state more explicitly that:

    - the x-intercept (when v = 0) occurs at x = h

    - the v-intercept (when x = 0) occurs at y = √(2gh)
     
  4. Jun 22, 2011 #3
    but how the curve will be. I mean will it open up or down?

    Thanks for your help :)
     
    Last edited: Jun 23, 2011
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Classical physics (phase diagram
  1. Phase change diagram (Replies: 3)

  2. Phase diagram question (Replies: 1)

  3. Classical physic (Replies: 2)

Loading...