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dirac1902

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A ball of mass m rests at times t less than 0, at height h above the ground. at time t=0 the ball is released and fell on the ground after hitting the ground, the ball rests there.

a) x represents distance from the ground, drive and expression for the phase diagram when the ball moving toward the ground. and draw it and find where v and x meet the axis's.

The attempt at a solution

1/2(mv^2)= mg(h-x)

v=sqrt(2g(h-x)) #

the graph will be a curve (square root) the start will be when x=h and then when it hits the ground will have max v so the position will be zero and v is max.

Thanks

a) x represents distance from the ground, drive and expression for the phase diagram when the ball moving toward the ground. and draw it and find where v and x meet the axis's.

The attempt at a solution

1/2(mv^2)= mg(h-x)

v=sqrt(2g(h-x)) #

the graph will be a curve (square root) the start will be when x=h and then when it hits the ground will have max v so the position will be zero and v is max.

Thanks

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