Clausius-Clapeyron equatioin's constant for methanol

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SUMMARY

The Clausius-Clapeyron equation is represented as lnP = A - C/T, where A and C are constants that vary based on the material and specific conditions such as temperature and pressure. For water, steam tables provide the necessary values for A and C, allowing for interpolation of pressure data at specific temperatures. This equation demonstrates a linear relationship between lnP and 1/T, which can be utilized for accurate predictions within defined temperature ranges.

PREREQUISITES
  • Understanding of the Clausius-Clapeyron equation
  • Familiarity with thermodynamic principles
  • Knowledge of pressure and temperature units (hPa and K)
  • Ability to interpret steam tables
NEXT STEPS
  • Research the specific values of A and C for various substances using steam tables
  • Learn how to perform data interpolation using the Clausius-Clapeyron equation
  • Explore the application of the Clausius-Clapeyron equation in phase transition studies
  • Investigate the relationship between temperature, pressure, and phase changes in different materials
USEFUL FOR

Chemists, physicists, and engineers involved in thermodynamics, particularly those studying phase transitions and vapor pressure relationships.

connard
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Hi everyone!
I'm searching for the constants in Clausius-Clapeyron equation

lnP=A-C/T

I'ld like to know the value of A and C. (for Pressure unity is hPa and Temperature is K )

Thanks
 
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connard said:
Hi everyone!
I'm searching for the constants in Clausius-Clapeyron equation

lnP=A-C/T

I'ld like to know the value of A and C. (for Pressure unity is hPa and Temperature is K )

Thanks
They depend on the material under consideration, and on conditions like temperture and pressure. For water you could look at some steam tables. What the equation says is that log P and 1/T are linear as a 1st approximation. The equation can be used to interpolate a data set. Ie you know P(T) for water in 5 K increments from 273 to 373 and want to know P(300.62).
 

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