Closed orbits in hydrogen when exposed to vertical electric field

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SUMMARY

This discussion focuses on determining classical turning points in semi-parabolic coordinates for the hydrogen atom subjected to a vertical electric field. The equations derived from the Hamiltonian are critical for finding closed orbits, specifically when the electron is launched vertically along the y-axis. The key equations are simplified at the classical turning point, where kinetic energy equals zero, leading to the quartic equation that defines the turning point for the orbit. The discussion references the article "Classical, semiclassical, and quantum dynamics in the lithium Stark System" from Physical Review A, which provides foundational insights into this analysis.

PREREQUISITES
  • Understanding of Hamiltonian mechanics
  • Familiarity with semi-parabolic coordinates
  • Knowledge of quantum mechanics postulates
  • Basic grasp of classical and quantum dynamics
NEXT STEPS
  • Study the Hamiltonian formulation in quantum mechanics
  • Explore the implications of electric fields on atomic orbits
  • Investigate the properties of semi-parabolic coordinates
  • Learn about the commutation relations in different coordinate systems
USEFUL FOR

Physicists, quantum mechanics students, and researchers interested in atomic dynamics under external electric fields will benefit from this discussion.

rydberg157
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Hi.
I am trying to find the classical turning points in semi-parabolic coordinates for the hydrogen atom when an electric field is being applied to it in the y-axis. I am reading an article for those who are interested called Classical, semiclassical, and quantum dynamics in the lithium Stark System published in Physical Review A Volume 51, Number 5. It gives me the following three separated equations based on the Hamiltonian:

.5 * (pu)^2 + .5*F*u^4 - E(u^2) = eu
.5 * (pv)^2 - .5*F*u^4 - E(u^2) = ev

and eu + ev = 2

u and v are semi-parabolic position coordinates. eu and ev are separation constants.
The article also says that for the purposes of finding closed orbits, that's what I am looking for, E = scaled energy and F = 1. Scaled energy can be picked to be an arbitrary number. Scaled energy = E / (F^.5)

I know that at the classical turning point the kinetic energy is equal to 0 so the equations above simplify to

.5*u^4 - (scaled_energy)*u^2 = eu
-.5*v^4 - (scaled_energy)*v^2 = ev

Finding the classical turning point will hopefully help me determine closed orbits for hydrogen as they give me two integrals for determining when an orbit is closed if the electron is launched at a certain angle in a Field=1 and and Energy=Scaled Energy.

I have figured out that in the primitive orbit of hydrogen where the electron is launched vertically in the y-axis, parallel to the field, the electron will have u = 0 position and a velocity in the u direction = 0, so the quartic equation

0.5v^4 - (scaled_energy)*v^2 = ev = 2

will determine the classical turning point for that orbit.

Thank you
 
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rydberg157 said:
Hi.

... I have figured out that in the primitive orbit of hydrogen where the electron is launched vertically in the y-axis, parallel to the field, the electron will have u = 0 position and a velocity in the u direction = 0, so the quartic equation ...


Thank you

I am not familiar with semi-parabolic coordinates, but I have to say that conclusion looks suspicious to me. It seems to violate one of the postulates of QM, which says that a position operator along an orthogonal coordinate q, and the corresponding momentum operator pq, must obey the commutation relation [q,pq]=ihbar. I know that is the case for Cartesian coordinates, and I believe that relation also holds in any other coordinate system, but I am not completely sure of that.
 

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