Closed subspace of a Sobolev Space

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SUMMARY

The discussion focuses on proving that the space \tilde{W}^{1,2}(\Omega), consisting of functions in W^{1,2}(\Omega) with an average value of 0, is a closed subspace of W^{1,2}(\Omega). The participant is analyzing a convergent sequence of functions \tilde{w}_k in \tilde{W}^{1,2}(\Omega) converging to a function w in W^{1,2}(\Omega). The challenge lies in demonstrating that the limit function w retains the property of having an average value of 0, thus confirming its membership in \tilde{W}^{1,2}(\Omega).

PREREQUISITES
  • Understanding of Sobolev spaces, specifically W^{1,2}(\Omega)
  • Knowledge of convergence in functional spaces
  • Familiarity with properties of average values of functions
  • Basic concepts of distributional derivatives
NEXT STEPS
  • Study the properties of closed subspaces in functional analysis
  • Learn about convergence criteria in Sobolev spaces
  • Explore the implications of bounded sequences in Sobolev spaces
  • Investigate the role of average values in function spaces
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Mathematicians, particularly those specializing in functional analysis and Sobolev spaces, as well as students tackling advanced topics in analysis and PDEs.

lmedin02
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Homework Statement



I am considering the space \tilde{W}^{1,2}(\Omega) to be the class of functions in W^{1,2}(\Omega) satisfying the property that its average value on \Omega is 0. I would like to show that \tilde{W}^{1,2}(\Omega) is a closed subspace of W^{1,2}(\Omega).

Homework Equations


W^{1,2}(\Omega) is the space of L^2(\Omega) so that their distributional derivative also lie in L^2(\Omega).


The Attempt at a Solution



It is clear that \tilde{W}^{1,2}(\Omega) is a subspace of {W}^{1,2}(\Omega). So I now consider a convergent sequence of functions \tilde{w}_k in \tilde{W}^{1,2}(\Omega) converging to a function w in W^{1,2}(\Omega). I am having trouble showing that w has average value 0 and hence belongs in \tilde{W}^{1,2}(\Omega). Any suggestions.
 
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I am having a hard time making this conclusion. How about if the sequence is bounded?
 

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