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p.tryon

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- Thread starter p.tryon
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p.tryon

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- #2

Hootenanny

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I'm afriad that I don't understand the question. Static friction occurs when two bodies are stationary relative to each other, whereas kinetic friction occurs when the two bodies are in relative motion.

When two bodies moving relative to each other are in contact, there is said to be no static friction.

- #3

p.tryon

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According to the following calculations they are the same

From here on:

Coefficient of friction C

Frictional force F

Normal Force Fn

F = C.Fn

Therefore

C = F / Fn

1. At rest:

F = WSin45 and Fn = Wcos45

Therefore

C = WSin45 / Wcos45

2. Sliding at a constant speed:

Since F is equal to the opposite component of gravity (WSin45) - Newton's first law! the equation and therefore answer is exactly the same for the coefficient of dynamic friction:

C = WSIn45 / Wcos45

- #4

Doc Al

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In general, they would be different.Imagine a box of weight W sliding at a constant speed down a slope at an angle of 45 degrees. Imagine the same box at rest on the same slope. The two types of friction are different (static and kinetic) and the two coefficients of friction should be different (or should they?)

The relationship F = μN is only true forAccording to the following calculations they are the same

From here on:

Coefficient of friction C

Frictional force F

Normal Force Fn

F = C.Fn

Therefore

C = F / Fn

For

- #5

rcgldr

Homework Helper

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This would only imply that the slope angle and coefficient of dynamic friction were "balanced" such that they resulted in equal and opposing forces from gravity and dynamic friction (therefore no acceleration), and that dynamic friction was independent of speed within the speed range experienced, excluding a speed of zero. The constant speed (not including zero speed) case occurs when tan(slope angle) = coefficient of dynamic friction.If an object slides down a slope at a constant speed is the coefficient of static friction the same as the coefficient of dynamic friction?

If the speed were zero, then the friction would be due to a normally higher coeffcient of static (than dynamic) friction, and the slope could be increased without the box moving. If the box was pushed, then the box would accelerate down the steeper slope instead of sliding at constant speed.

There are pairs of surfaces where static and dynamic friction are about the same, such as teflon on teflon.

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