Coefficient of friction Problem

In summary: I am still confused.If you have any information that could help me understand this problem I would be grateful.Thank you!In summary, the problem involves a small box resting on a larger box on a table, both boxes accelerating together when a horizontal force is applied to the larger box. The small box does not slip on the larger box. The acceleration of the pair of boxes is 2.5 m/s^2. The task is to determine the smallest coefficient of friction between the boxes that will prevent slippage. While the coefficient of static friction formula (us = Fs / Fn) requires the knowledge of mass or normal force, utilizing the fact that the boxes do not slip and the only horizontal force acting on the smaller box
  • #36
Exactly correct.

Fs = ma = μmg
Thus, μ = a/g.
 
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  • #37
All right. Thanks for the help!
 

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