(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 5.20 kg block is set into motion up an inclined plane with an initial speed of v0 = 7.70 m/s. The block comes to rest after traveling 3.00 m along the plane, which is inclined at an angle of 30.0° to the horizontal.

(a) For this motion, determine the change in the block's kinetic energy.

I got -154.154 (correct)

(b) For this motion, determine the change in potential energy of the block-Earth system.

I got 75.6 (correct)

(c) Determine the frictional force exerted on the block (assumed to be constant).

I got 26.18 (correct)

(d) What is the coefficient of kinetic friction?

However, I could not figure this out for the life of me. Please help with the kinetic friction?

2. Relevant equations

I think the coeff. can be found with f=μmgCosθ , however my answer keeps coming out wrong...

3. The attempt at a solution

after using the previous formula, I came out with a value of μ=3.327 (26.18=u(5.2)(9.81)(cos(30))

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# Coefficient of Kinetic Friction

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