1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Coeffiecient of Kinetic Friction problem? (Shuffleboard and Distance traveled)

  1. Oct 14, 2008 #1
    Coeffiecient of Kinetic Friction problem??? (Shuffleboard and Distance traveled)

    1. The problem statement, all variables and given/known data

    A shuffleboard disk is accelerated to a speed of 5.8m/s and released. If the coefficient of kinetic friction between the disk and the concrete court is 0.31, how far does the disk go before it comes to a stop? The courts are 15.8m long.

    Known info:
    vi = 5.8m/s
    vf = 0m/s
    [tex]\mu[/tex]k = 0.31


    2. Relevant equations

    I have no idea!

    3. The attempt at a solution

    So, I originally tried vf2 = vi2+ 2a[tex]\Delta[/tex]d, but that would make no sense because I used 15.8 as the distance but then the problem would be solved....
     
  2. jcsd
  3. Oct 15, 2008 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi glindawantsme! Welcome to PF! :smile:

    (have a delta: ∆ :smile:)

    Yes, that is the right equation …

    So what is vf? what is vi? and what is a?

    Put them all in, and find ∆d. :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Coeffiecient of Kinetic Friction problem? (Shuffleboard and Distance traveled)
  1. Shuffleboard problem (Replies: 6)

Loading...