Exploring Odds and Probability of a Symmetric Coin Toss

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The probability of getting an even number of tails in 491 tosses of a symmetric coin is indeed 50%. This conclusion is based on the principle of symmetry, as the outcomes of heads and tails are equally likely. Since the total number of tosses is odd, the distribution of tails must balance between even and odd counts. Mathematical proofs can support this conclusion without needing complex formulas. The symmetry of the coin toss ensures that the likelihood of achieving an even number of tails is equal to that of achieving an odd number.
kaitoli
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Hi everyone

There is a question which I find very hard to solve and it goes like this..

A symmetric coin with heads on one side and tails on the other side is tossed 491 times after one another. The total amount of times you get tails is either even or odd. Is the probability that you get an even amount of tails exactly 50%? And the question requires a strong mathematical evidence, e.g. a formula.
 
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Mathematical proofs don't always require formulas. In this case, the basic argument is symmetry (assuming a fair coin). Therefore the probability of n tails and m heads is the same as the probability of m tails and n heads, where n and m are arbitrary with n+m=491.
 
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