Coin Weight Variation Tolerance Calculation

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SUMMARY

The discussion centers on calculating the allowable variation in the radius of coins minted for the federal government, ensuring they weigh within 1/50 of their ideal weight. The participant outlines assumptions of homogeneity, isotropy, and constant thickness, leading to the conclusion that the radius variation must be within 1/100. The mathematical derivation involves density, volume, and weight relationships, confirming the calculations are accurate and consistent with the problem's requirements.

PREREQUISITES
  • Understanding of basic physics principles, particularly mass, weight, and density.
  • Familiarity with geometric concepts, specifically the area of a circle and volume calculations.
  • Knowledge of calculus, particularly differentiation as it applies to volume and mass changes.
  • Basic understanding of isotropic and homogeneous materials in manufacturing contexts.
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  • Research the implications of material properties on manufacturing tolerances.
  • Learn about the effects of dimensional variations on product performance in engineering.
  • Explore advanced topics in geometric tolerancing and its applications in coin minting.
  • Investigate density variations in different materials and their impact on weight calculations.
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This discussion is beneficial for manufacturing engineers, quality control specialists, and students studying materials science or mechanical engineering, particularly those involved in precision manufacturing and product design.

donjt81
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Find variation - really need help!

guys i really need your help on this. I don't even know which section to look for here. can some one please get me started for this problem.

Problem: A manufacturer contracts to mint coins for the federal government. how much variation dr in the radius of the coins can be tolerated if the coins are to weigh within 1/50 of their ideal weight? Assume the thickness does not vary.
 
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I do not know if this is correct, but what I'm thinking is:

1) assume the material is homogeneous and isotropic
2) assume the thickness is constant
3) assume the volume may be written as the product of the area of a circle and its constant height

Then, we can write the mass as the usual density, i.e. [tex]m=\rho V[/tex] then the weight is just g times the mass. So, note that
[tex]dm = \rho dV=\rho (2\pi r dr) t[/tex]
where t is the constant thickness. So, if we compare to its ideal weight, note the constant g drops out, along with a lot of other stuff. So
[tex]\frac{dm}{m} = \frac{\rho dV}{\rho V}=\frac{2dr}{r}[/tex]
So, plugging in what we know we have
[tex]\frac{1}{50} =\frac{2dr}{r} \Rightarrow \frac{dr}{r}=\frac{1}{100}[/tex]
So the variation in the radius must be within 1/100. Does this make sense? I think it works.
 
Thanks xman... yes it looks correct...

can anyone else look at it and confirm it? I want to make sure i do the homework right.
 

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