- #351
mfb
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But what was y?
On the milk boxes - for missing letters. Possibly taken hostage by foreign names.mfb said:But what was y?
It's time for philosoraptor to participate in this thread...mfb said:A distaraptor would walk a lot, and a timeraptor (tempusraptor?) would have a long life?
You've said that before, in 2029!Stavros Kiri said:PF profile:
Age: "-38"
Birth date: May 1, 2055
Occupation: historian, time traveller
Favourite area of science: Relativity, time travel etc.
Hobbies-interests: time slip, teleportation, time spa, history of early 21st century ... etc.
(i.e. the usual)
Ouoooops! time slip ...DrGreg said:You've said that before, in 2029!
Nobody wished me Happy Birthday!Stavros Kiri said:PF profile:
Age: "-38"
Birth date: May 1, 2055
Occupation: historian, time traveller
Favourite area of science: Relativity, time travel etc.
Hobbies-interests: time slip, teleportation, time spa, history of early 21st century ... etc.
(i.e. the usual)
DrGreg said:You've said that before, in 2029!
fresh_42 said:Math was easy in the Roman empire. x was always 10.
There was only one [geopolitical] variable in the Roman empire: 'Roman Power'. And it was always a 10.mfb said:But what was y?
But how could ##X## be constant if ##V## was 5? A paradox.fresh_42 said:Math was easy in the Roman empire. x was always 10.
Was it a quantum cop?kuruman said:Why were ##p_x## and ##x## cited by the traffic cop?
They were caught driving together in the commuter lane.
##V(t) = DX(t)## but ##t##empus fugit, ergo ##V = DX =## dividere ##X##:DrGreg said:But how could ##X## be constant if ##V## was 5? A paradox.
5 = 510? Another paradox.fresh_42 said:ergo ##V = DX##
That's because these idiots killed Archimedes. No wonder they couldn't differentiate!DrGreg said:5 = 510? Another paradox.
Thus 7 = 10. Another paradox!mfb said:V II = X, if we skip multiplication signs between numbers.
##1\,0## can be any number greater than ##1##.Stavros Kiri said:Thus 7 = 10. Another paradox!
Proof?fresh_42 said:##1\,0## can be any number greater than ##1##.
And if we don't skip multiplication signs ##515 = LXV = L \times V = 50 \times 5 = 250##mfb said:V II = X, if we skip multiplication signs between numbers.
Roman accelerations were also constant:$$a = v \frac {dv}{dx} = 5 \cdot \frac {505}{510} \approx 4.95$$DrGreg said:But how could ##X## be constant if ##V## was 5? A paradox.
fresh_42 said:##1\,0## can be any number greater than ##1##.
##1\;0=1\cdot b^1 + 0 \cdot b^0## and now chose a basis ##b>1## of your choice.Stavros Kiri said:Proof?
Then always 2 = 3 = ... = 10 = etc. , and we don't need Roman power anymore!fresh_42 said:##1\;0=1\cdot b^1 + 0 \cdot b^0## and now chose a basis ##b>1## of your choice.
3 = iii = -i = -1?DrGreg said:And one more: ##2 = ii = i^2 = -1##.
How soft and "micro" was the apple?davenn said: