Collider Luminosity Calculation

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SUMMARY

The discussion centers on calculating the average luminosity of a collider with specific parameters: an electron current of 10 milliAmps and a positron current of 5 milliAmps, a ring radius of 100 m, and electron and positron bunches with a radius of 1 µm and length of 2 mm. The formula for luminosity, L = N_1 N_2 / A * f, is highlighted, but participants express confusion regarding the incorporation of current and ring radius into the density calculations. Key insights include the relationship between current, charge, and time, leading to the determination of the average time between electrons.

PREREQUISITES
  • Understanding of collider physics and luminosity calculations
  • Familiarity with the formula L = N_1 N_2 / A * f
  • Knowledge of current, charge, and their relationship (Current = Charge / Time)
  • Basic geometry of circular motion in colliders (e.g., calculating circumference)
NEXT STEPS
  • Research the calculation of luminosity in particle colliders
  • Learn about the effects of bunch density on collider performance
  • Study the relationship between current, charge, and time in particle physics
  • Explore the geometry of circular colliders and its impact on particle collisions
USEFUL FOR

Students and researchers in particle physics, particularly those involved in collider experiments and luminosity calculations, will benefit from this discussion.

renegade05
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Homework Statement


A collider has an average electron current of 10 milliAmps and an average positron current of
5 milliAmps.If the ring radius is 100 m and there is one electron bunch and one positron bunch
with uniform density, radius 1 µ and length 2 mm, what is the average luminosity in cm–2s–1 ?

Homework Equations


L=N_1 N_2/A * f
density = N/(AT)

The Attempt at a Solution


Ok so I know the target thickness (T) is 2mm with and Area (A) of pi * (1µ)^2
The density I am having a problem with.
I don't know how to incorporate the current given or the ring radius.

Just having a hard time with this question in general. Not sure where to start or where to plug everything in. Please help - thanks!
 
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You don't need a density.

How frequent do the electrons pass your collision point? You can assume that they are high-energetic and move with roughly the speed of light.
Which current does a specific amount of charge give, using the information calculated above?
 
Ok so Current = Charge/ Time. So I can solve for the time?! Still a very confused on how to solve this. sorry :(
 
Yes you can find the revolution time. You know the speed of the electrons/positrons and the collider geometry (ring with 100m radius).
 
Ok so for the electrons I get a time of... Time = 1.602X10^-19 / 0.01 = 1.6x10^-17 seconds ?
and Distance traveled will be R=2pi*100 = 200pi
NOW WHAT?!
 
renegade05 said:
Ok so for the electrons I get a time of... Time = 1.602X10^-19 / 0.01 = 1.6x10^-17 seconds ?
What did you calculate here? What are the units?

renegade05 said:
and Distance traveled will be R=2pi*100 = 200pi
Don't forget the units.
You know distance and speed, that allows to calculate how long the electrons need for one round in the ring.
 
Ya I have the units for the first one. They are seconds. I am not sure what that time is referring to though or how to use it.

The distance traveled will be 200pi Meters, I don't know the speed though...
 
renegade05 said:
Ya I have the units for the first one. They are seconds.
No they are not. The first value seems to be the elementary charge, which has units of a charge (Coulomb), and I have no idea what the 0.01 is supposed to represent. It is hard to help if you throw in completely unexplained calculations.
The distance traveled will be 200pi Meters, I don't know the speed though...
See post 2.
 
Current = Charge/ Time
The current given for the electron beam is 0.01 Amps
The charge of an electron is 1.602X10^-19
Thus Charge/Current = Time
right?
 
  • #10
Ah... okay, that is the average time between electrons then.
 

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