Electric field from a rotating coaxial ring

Click For Summary

Homework Help Overview

The problem involves a rotating coaxial ring with a uniform charge density, where participants are tasked with finding the magnetic field at a distance from the ring's axis. The subject area pertains to electromagnetism, specifically the behavior of magnetic fields generated by moving charges.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the magnetic field of a rotating ring to that of a stationary ring with current, questioning the appearance of a factor of 1/2 in their results. Some participants question the assumptions made regarding the current and its relation to the charge density and angular velocity.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the original poster's assumptions and the factors affecting the magnetic field calculation. There is acknowledgment of a potential error in the problem statement regarding the title, which may influence the interpretation of the problem.

Contextual Notes

Participants note the discrepancy in the expected results and the original poster's confusion about the factor of 1/2, indicating a need for clarification on the relationship between charge density, current, and the resulting magnetic field.

Spriteling
Messages
34
Reaction score
0

Homework Statement



A wire with uniform charge density λ per unit length is bent into a ring of radius a and rotates with angular velocity ω about an axis through its centre and perpendicular to the plane of the ring. Find the magnetic field on the axis at a distance z from the ring.


Homework Equations



The magnetic field at a distance z from a ring with current I flowing through it is

B = \frac{\mu_0 I a^2}{2(a^2 + z^2)^{3/2}}\hat{z}


The Attempt at a Solution



I assumed that the magnetic field would be the same as in a stationary ring with current I, where in this case I would be given by λωa. However, the solution appears to be less than this by a factor of 1/2 and I am completely at a loss as to where this extra 1/2 comes from.
 
Physics news on Phys.org
Anyone?
 
Ack, I just realized that the title should be magnetic field, not electric field.
 
I think you are right.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
16K
Replies
11
Views
3K
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K