Collision between two balls, determine the speed of other ball

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SUMMARY

The discussion focuses on calculating the speed of a second billiard ball after a glancing collision, using the equation 0=mv1sin30- mv2sin60. The calculated speed for the first ball (v1) is 0.087 m/s, derived from the equation with the initial speed of 0.05 m/s. Participants clarify the distinction between elastic and glancing collisions, emphasizing that glancing collisions occur at an angle while elastic collisions conserve both energy and momentum.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with trigonometric functions in physics
  • Knowledge of elastic vs. inelastic collisions
  • Basic skills in significant figures and calculations
NEXT STEPS
  • Study the principles of momentum conservation in collisions
  • Learn about elastic collision equations and their applications
  • Explore the role of angles in glancing collisions
  • Review significant figures and their importance in scientific calculations
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for examples of collision calculations.

dani123
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Homework Statement



This figure shows two identical billiard balls before and after a glancing collision. Determine the speed of the other ball.

module 2 num 4.jpg


Homework Equations



0=mv1sin30- mv2sin60


The Attempt at a Solution



v1= [(0.05m/s)sin60]/(sin(30))= 0.087 m/s


Here I am looking for someone to check my calculations and that I have respected the proper number of significant figures. I was also wondering if anyone could explain to me what the difference is between an elastic collision and a glancing collision? Thanks so much in advance!
 
Physics news on Phys.org
A glancing collision is simply a type of collision where the objects strike at an angle. Elastic and inelastic collisions have to do with the energy and momentum conserved. Your answer looks right to me.
 

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