Collision- I don't think conservation of linear momentum can be established

AI Thread Summary
The discussion revolves around a collision problem involving two particles on a table, where one particle is moving west and the other north. The user expresses doubt about the conservation of linear momentum during the interaction, suggesting that the duration of the interaction (2 seconds) implies external forces may be at play. However, responses clarify that linear momentum is conserved as long as no external forces act on the system, despite mechanical energy potentially not being conserved. The user is encouraged to analyze the problem further to determine the second particle's direction and speed post-interaction. The conversation highlights the distinction between momentum and energy conservation in collision scenarios.
fluidistic
Gold Member
Messages
3,928
Reaction score
272

Homework Statement


The system is a table with 2 particles on it. A particle of mass 3kg is going at West with a speed of \frac{1m}{s}. Another particle of 4 kg is going to North with a speed of \frac{5m}{s}. When they are close enough they interact during 2 seconds and the first particle leaves out with an angle of about 53° (\arctan \left( \frac{4}{3}\right)° ) measured from East to North, with a speed of \frac{5m}{s}.
a)Find the magnitude and the direction of the second particle after the interaction.
b)... (I'll do it alone)
c)Tell whether the collision is an explosive one or a plastic one.



2. The attempt at a solution I never faced such a problem before and I was going to ask to a helper at my University tomorrow but I just can't wait for that...
I'm more than 100% sure that the linear momentum is not conserved (2s is a lot for an interaction, furthermore that's why they ask if it was an explosive or a plastic collision. That means that the mechanical energy is not conserved hence nor is the linear momentum).
My guess : The second particle will leave out following an opposite direction with respect to the first particle but I'm not sure at all. If so, I don't know why it is like this. And much less I can say about its speed.
How can I tackle this problem?
Thanks in advance!
 
Physics news on Phys.org
fluidistic said:
I'm more than 100% sure that the linear momentum is not conserved (2s is a lot for an interaction, furthermore that's why they ask if it was an explosive or a plastic collision. That means that the mechanical energy is not conserved hence nor is the linear momentum).
Just because mechanical energy might not be conserved has nothing to do with whether momentum is conserved. As long as they only interact with each other, linear momentum will be conserved.
 
Thank you Doc Al for your very fast reply. I am... :eek: but now I remember a university helper saying that if the interaction lasts quite long the linear momentum wouldn't be conserved if there is an external force acting on the particles... ok here there is no force that influence the system.
But still it's strange that the first particle gets such a direction. Maybe an explosion or something like that. (I'll try to find out).
Thanks again...
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top