Column space of positive semidefinite matrix

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Discussion Overview

The discussion revolves around proving a relationship involving the range of a positive semidefinite matrix and the null space of a matrix formed by subtracting a scalar multiple of the identity matrix from it. The focus is on the implications of nonzero eigenvalues and their corresponding eigenspaces.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks how to prove that the range of matrix A, denoted R(A), is equal to the sum of the null spaces of (A - λI) for nonzero eigenvalues λ of A.
  • Another participant provides a partial argument showing that if y is in R(A), then y can be expressed as Ax = λx, and that if (A - λI)x = 0, then x is in N(A - λI).
  • A question is raised about whether this implies that y is the sum of the eigenvectors of A.
  • A later reply introduces the case of the zero matrix, noting that it is positive semidefinite and that its range and null space behave in a particular way, suggesting a potential counterpoint to the original claim.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the proof or the implications of the statements made. Multiple viewpoints and questions remain unresolved.

Contextual Notes

There are limitations regarding the assumptions made about the nature of the eigenvalues and the specific properties of the matrices involved. The discussion does not clarify the conditions under which the proposed relationships hold.

td21
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how to prove that
[tex]R(A)=\text{sum of} N(A-\lambda I)[/tex]?

[itex]\lambda[/itex] is nonzero eignevalues of A
 
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well i can show that
1)if y[itex]\in[/itex]R(A), then y=Ax=λx.
2)As (A−λI)x=0, x[itex]\in[/itex]N(A−λI).

But how can we show that y[itex]\in[/itex] sum of N(A−λI)?

thanks
 
Does this mean y= sum of eignevectors of A?
 
anyone?thanks
 
Hi td21! :smile:

What about the zero matrix? This is positive semidefinite, and

[tex]R(0)=0~\text{and}~N(0-\lambda I)=N(0)=\text{entire space}[/tex]
 

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