Columns of liquids at different temperuatures

  • Thread starter Thread starter Amith2006
  • Start date Start date
  • Tags Tags
    Columns Liquids
Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving the balance of two vertical columns of liquid at different temperatures and lengths. The original poster attempts to determine the coefficient of absolute expansion of the liquid based on the pressures exerted by the columns.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the heights and densities of the liquid columns, questioning the calculations and assumptions made regarding the densities at different temperatures. Some participants highlight a potential error in the original setup regarding the height of the second column.

Discussion Status

There is ongoing exploration of the problem with participants providing different perspectives on the calculations. Some guidance has been offered regarding the definition of the volumetric thermal expansion coefficient, but no consensus has been reached on the correct approach or solution.

Contextual Notes

Participants note that the change in volume with temperature may complicate the calculations, suggesting that the problem involves more than just simple linear expansion. There is also mention of discrepancies between the calculated and expected values for the coefficient of expansion.

Amith2006
Messages
416
Reaction score
2
Sir,
Please help me with this problem.
# A vertical column of liquid 50 cm long at 50 degree Celsius balances another column of same liquid 60 cm long at 100 degree Celsius. What is the coefficient of absolute expansion of the liquid?
I solved it in the following way:
Pressure exerted by 50 cm of liquid at 50 degree Celsius = Pressure exerted by 60 cm of liquid at 100 degree Celsius.
Hence, (h1)(d1)g = (h2)(d2)g
50 x d1 x g = 100 x d2 x g
d1 = 2 x d2 -------- (1)
We know that d1 = d2[1 + r(dt)] --------- (2)
Where d1 = density at T1 temperature
d2 = density at T2 temperature(Here T1<T2)
r = coefficient of cubical expansion of the liquid
dt = T2 – T1
Substituting (1) in (2) we get,
2 x d2 = d2[1 + (r x 50)]
By solving we get,
r = 0.004 / deg Celsius
But the answer given in my book is 0.005/ deg Celsius. Please advice.
 
Physics news on Phys.org
Please respond.
 
Amith2006 said:
Pressure exerted by 50 cm of liquid at 50 degree Celsius = Pressure exerted by 60 cm of liquid at 100 degree Celsius.
Hence, (h1)(d1)g = (h2)(d2)g
50 x d1 x g = 100 x d2 x g
h2=60 (not 100) cm
 
Amith2006 said:
Sir,
Please help me with this problem.
# A vertical column of liquid 50 cm long at 50 degree Celsius balances another column of same liquid 60 cm long at 100 degree Celsius. What is the coefficient of absolute expansion of the liquid?
I solved it in the following way:
Pressure exerted by 50 cm of liquid at 50 degree Celsius = Pressure exerted by 60 cm of liquid at 100 degree Celsius.
Hence, (h1)(d1)g = (h2)(d2)g
50 x d1 x g = 100 x d2 x g
d1 = 2 x d2 -------- (1)
We know that d1 = d2[1 + r(dt)] --------- (2)
Where d1 = density at T1 temperature
d2 = density at T2 temperature(Here T1<T2)
r = coefficient of cubical expansion of the liquid
dt = T2 – T1
Substituting (1) in (2) we get,
2 x d2 = d2[1 + (r x 50)]
By solving we get,
r = 0.004 / deg Celsius
But the answer given in my book is 0.005/ deg Celsius. Please advice.
Though I typed it wrongly, I solved it by using h2 = 60cm. Is it right?
 
Amith2006 said:
Though I typed it wrongly, I solved it by using h2 = 60cm. Is it right?
The problem here is that the change in volume is significant. So the rate of change in volume increases as the volume and temperature increase, does it not? It is a little more complicated than simple linear expansion.

AM
 
Last edited:
Amith, you need to use :

[tex]\gamma = \frac{1}{V} \frac{\partial V}{\partial T}[/tex]

This is the definition of volumetric thermal expansion coefficient.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
24
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K