Compare y=Cos(x) and transformation HELP

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SUMMARY

The graph of y=-3 cos(2θ + π/4) differs from y=cos(θ) due to a vertical stretch by a factor of 3 and an upward translation of 3 units. Additionally, the horizontal translation is determined by rearranging the equation to identify h, which equals -π/8, indicating a leftward shift of π/8 units. The parameter a, set to 2, signifies that the function oscillates twice within an interval of 2π. Understanding these transformations is essential for accurately graphing trigonometric functions.

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aisha
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How does the graph y=-3 \cos (2\theta+ \frac {\pi} {4}) +3 Differ from the graph of y=\cos\theta

I think this graph is different because it has a vertical stretch by a factor of 3 and is translated upwards 3 units but I am not sure how to rearrange this to find the horizontal translation and the horizontal compression/stretch

Could someone please help me out! THANKS :smile:
 
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A computer program can be helpful - enjoy changing parameters and understanding the corresponding changes of the graph.
 
Let's suppose that theta is replace by t.
in cos(2t + pi/4) can be written cos2(t+pi/8) that you can compare with cosa(t-h) where the parameter h gives you how many units the curve is translate to the right (when h >0) or to the left (when h<0)
Now you can see that in your problem h = -pi/8, so the translation is to the left pi/8 units. The parameter a = 2 tells you the number of times it osccillates in the intervall length of 2 pi; in the problem you have 2 complete oscillations in an intervall length of 2 pi.
 

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