1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Comparing structural bending strength

  1. Nov 4, 2013 #1
    Hello,

    Not sure how to go about solving this problem:

    What outer diameter must a 2mm thick hollow rod have in order to have the same structural bending strength as a solid rod with diameter of 7mm? Also compare the weight per unit length of the two rods. Assume that material is stainless steel (E=180MPa) having weight density of 7.78 x 10^4N/m^3.

    Does the 2mm thick refer to the length of the hollow rod? Where does weight density play into the equation?

    Given equations:
    stress = Mc/I

    Bending rigidity -> ymax= cFl^3/EI

    Thank you in advance for any information you can provide.
     
  2. jcsd
  3. Nov 4, 2013 #2
    Ok so this is what I have so far:

    for the soild bar
    find area
    A=1/4(pie)(dia)^2 -> =38.48mm^2

    find moment
    I=Pie/64(D^4) -> = 117.85mm^4

    Find stress
    stress=My/I where M=bending moment, y=neutral axis, I=moment
    -> =M(3.5)/117.85 -> stress=.0297(M)
    for this equation I don't know how to find M

    So to have the outer diameter of the hollow rod
    find the area
    A=pie((Do^2)-(Di^2)) where Do is outer dia and Di is inner dia

    solution for outer diameter is Do=4.03mm

    Is this the correct approach for that part of the problem??
     
  4. Nov 4, 2013 #3
    Still having some issues with how to compare the weight per unit length of the two rods. I'm given E=108x10^3MPa, weight density= 7.78x10^4N/m^3 for both rods, calculated I=117.85 for solid bar. Using the equation Ymax= cFl^3/EI where c=constant, l=1.

    So please advise on how to proceed here.

    Also a fix to the above post.
    using the I value from the solid and plugging that value into this equation for the hollow bar I=(pi/64)((Do^4)-(Di^4)) Do=7.0115mm^4 instead of the 4.03 value, is this correct?
     
  5. Nov 5, 2013 #4

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    You have that for a solid rod diameter D the 2nd moment of area is ##\frac{\pi D^4}{64}##. For a hollow rod, just treat it as the difference of two solid rods. I.e. subtract the 2d MoA of the missing part from what you would get if the rod were solid.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Comparing structural bending strength
  1. Bending Moments (Replies: 5)

  2. Bending stress (Replies: 5)

  3. Comparator Circuits (Replies: 2)

Loading...