Comparison Theorem and Limits of integration

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Painguy
Messages
118
Reaction score
0

Homework Statement



Why is it that when using the comparison theorem my limits of integration must be from a constant value to infinity and not from negative infinity to infinity?

For example ∫ x/(1+x^2) dx from -∞ to ∞
 
Physics news on Phys.org
Can you be more specific about what comparison theorem you are talking about?

For your example, notice that if ##x \geq 1##, you can easily check that
$$\frac{x}{1+x^2} \geq \frac{1}{2x}$$
What does that tell you?