Complex Analysis: Cauchy Integral Formula

Click For Summary
SUMMARY

The discussion centers on the application of the Cauchy Integral Formula from Sarason's "Complex Function Theory, 2nd edition." The problem involves evaluating the integral \(\int_{C} \frac{f(\zeta)}{\zeta-z} d\zeta\) where \(z\) is located outside the contour \(C\). The consensus is that the value of this integral is zero, as the integrand \(\frac{f(\zeta)}{\zeta-z}\) remains holomorphic over the entire contour \(C\) when \(z\) is outside of it.

PREREQUISITES
  • Understanding of holomorphic functions
  • Familiarity with the Cauchy Integral Formula
  • Knowledge of contour integration
  • Basic concepts of complex analysis
NEXT STEPS
  • Study the implications of the Cauchy Integral Theorem
  • Explore examples of holomorphic functions and their properties
  • Learn about contour integration techniques in complex analysis
  • Investigate the consequences of the Cauchy Integral Formula in various scenarios
USEFUL FOR

Students of complex analysis, mathematicians focusing on holomorphic functions, and educators teaching contour integration techniques will benefit from this discussion.

masterslave
Messages
8
Reaction score
0

Homework Statement


The problem, for reference, is from Sarason's book "Complex Function Theory, 2nd edition" and is on page 81, Exercise VII.5.1.

Let C be a counterclockwise oriented circle, and let f be a holomorphic function defined in an open set containing C and its interior. What is the value of the Cauchy Integral, [tex]\int_{C} \frac{f(\zeta)}{\zeta-z} d\zeta[/tex], when z is in the exterior of C?

Homework Equations


The Cauchy Integral formula, as mentioned in the problem.


The Attempt at a Solution


I haven't the slightest how to begin the problem. My intuition, though, tells me [tex]\int_{C} \frac{f(\zeta)}{\zeta-z} d\zeta=0[/tex]. Any insight is appreciated.
 
Physics news on Phys.org
If z is in the exterior of C then f(zeta)/(zeta-z) is holomorphic in zeta over all of C.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
32
Views
4K
Replies
4
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K