1. The problem statement, all variables and given/known data Compute the integral from 0 to 2∏ of: sin(i*ln(2e^(iθ)))*ie^(iθ)/(8e^(3iθ)-1) dθ (Sorry for the mess, I don't know how to use latex) 2. Relevant equations dθ=dz/iz sinθ = (z - z^(-1))/2i 3. The attempt at a solution So I tried to change it into a contour integral of a function of z with the substitutions dθ=dz/iz and sinθ = (z - z^(-1))/2i. The dθ part is nice because we have ie^(iθ) in the equation so it cancels out. However, the sin function is not a function of theta but of a complex variable. I tried to reduce the inside of the sin as follows: sin(i*ln(2e^iθ)) = sin(i*(ln2 + iθ)) = sin(i*ln2 - θ), but this doesn't really get me anywhere as the sin function is still not a function of theta. Am I on the right track? And can anyone point me in the right direction of how to continue from here? Any help is much appreciated.