Complex Circuit Analysis Simplification

jonlg_uk
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I have the following circuit...
circuit22.jpg


I have managed to derive an equation for U2:

u22.jpg


Now I want to substitute U2 into U1, in order to derive equation for U1

I have defined U1 as:

u11.jpg


Now I substitute U2 into the above equation. This is how far I get...I am stuck...


My circuit simulator is saying that U1 is equal to:


u11sol.jpg



However I cannot simplify to get this equation. Can someone please help I have spent hours trying to get U1 to look like the U1 that the simulator produces.


I thank you in advance.
 
Have you try to replace R1, R2 and E2 with his Thevenine equivalent circuit ?
Eth = R2/ ( R1 + R2 ) * E1 and Rth = R1||R2

attachment.php?attachmentid=43692&stc=1&d=1328795691.jpg


V3 = I * R3

[tex]I = \frac{Eth}{\sqrt{(Rth + R3)^2 + Xc^2)}} = \frac{E1*\frac{R2}{R1+R2}}{\sqrt{(R1||R2 + R3)^2 + Xc^2)}}[/tex]

And

[tex]V3 = \frac{E1*R2*R3}{(R1+R2)\sqrt{(R1||R2 + R3)^2 + Xc^2)}}[/tex]
 

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Last edited:
Jony130 said:
Have you try to replace R1, R2 and E2 with his Thevenine equivalent circuit ?
Eth = R2/ ( R1 + R2 ) * E1 and Rth = R1||R2

attachment.php?attachmentid=43692&stc=1&d=1328795691.jpg


V3 = I * R3

[tex]I = \frac{Eth}{\sqrt{(Rth + R3)^2 + Xc^2)}} = \frac{E1*\frac{R2}{R1+R2}}{\sqrt{(R1||R2 + R3)^2 + Xc^2)}}[/tex]

And

[tex]V3 = \frac{E1*R2*R3}{(R1+R2)\sqrt{(R1||R2 + R3)^2 + Xc^2)}}[/tex]

No I haven't tried this before, but I did just try it and I still can't derive U1. Perhaps I am being stupid...
 
A made a small error instead of V3 I should write U1

jonlg_uk said:
IMy circuit simulator is saying that U1 is equal to:
u11sol.jpg
What is the name of your simulation program?
 
Thanks for your help Jony, the simulator is giving me this equation:

u11sol.jpg


I haven't derived that myself^. When I expand out the equation you derived:


[tex]V3 = \frac{E1*R2*R3}{(R1+R2)\sqrt{(R1||R2 + R3)^2 + Xc^2)}}[/tex]

I still not can get a the equation looking like the simulator one.


BTW the simulator is called Solve Elec, you can download it for free.

[URL="http://www.physicsbox.com/indexsolveelec2en.html[/URL]
 
Last edited by a moderator:
Ah done it! you are right I was being stupid. I am upset with myself that I never thought to do a thevin equivalent :( thanks a lot for your help. I can sleep peacefully tonight.
 

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