- #1
Malgrif
- 18
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Homework Statement
Given (e^(ix) - 1)^2 , show that it is equal to 2-2cosx
Homework Equations
e^ix = cosx + isinx
The Attempt at a Solution
After subbing in Euler identity and expanding I get:
cos(x)^2+sin(x)^2-2cosx-2jsinx+2jcosxsinx + 1
after using the addtion formulas I get
cos(2x)+jsin(2x)-2cosx-2jsinx+1
seems like I'm missing a fundamental trig ID... Please help, and let me know if my approach is correct.
Thanks