Complex Fourier series of sin (t)

[unscientific]

In finding C_n, I arrived at a different answer. I got an extra factor of (1/i) instead, which came when you do the integral of each exponential with respect to t; so you get a factor of 1/i(1-n) and 1/i(1+n) respectively..

Did they intentionally leave that out?

 

[mathman]

http://www.math24.net/complex-form-of-fourier-series.html

The above may help.

This should be in one of the math forums.

 

[mathman]

Addition thought. f(t) = sint is its own Fourier series. exp(it) = cost + isint. Therefore c₁ needs a coefficient 1/i. I can't see what your disagreement is about. Perhaps you can give the details of your derivation.

 

[unscientific]

Addition thought. f(t) = sint is its own Fourier series. exp(it) = cost + isint. Therefore c₁ needs a coefficient 1/i. I can't see what your disagreement is about. Perhaps you can give the details of your derivation.

Sorry, I spotted my mistake!