Complex impedance and negative reactance

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The circuit analysis involves a voltage of v(t) = 100cos(ωt) and a current of i(t) = 2cos(ωt + π/3). The calculated impedance is Z = 46 - j19, indicating a negative imaginary part. This suggests that the circuit has more capacitive reactance than inductive reactance, but it does not provide enough information to determine if only capacitors are present. The conclusion is that while the negative reactance indicates capacitive dominance, the exact configuration of components remains unclear.
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Homework Statement



consider a circuit expressed by v(t)= 100cos \omega t
and i(t)=2cos(\omega t+\pi / 3) .

Find the reactance.

Homework Equations


Z=\frac{V}{I} = R+jX

The Attempt at a Solution



Z=\frac{100}{2\angle \pi /3} = 50\angle -\pi /3 = 46 - j19

Does the negative imaginary part mean there is simply more reactance from the capacitor than inductor? Or *only* cap?

thanks!
 
Last edited:
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There is not sufficient information to find if there is only capacitor or there is more capacitive inductance than inductive.
 
That makes sense, thank you!
 

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