Complex number and its conjugate problem help

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 3K views
blckndglxy
Messages
2
Reaction score
0

Homework Statement


Given that a complex number z and its conjugate z¯ satisfy the equation z¯z¯ + zi = -i +1. Find the values of z.

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
Hey, I think z.z-=1 but what's with the zi thing. Can you upload the picture of your question? Its not clear enough.
 
blckndglxy said:

Homework Statement


Given that a complex number z and its conjugate z¯ satisfy the equation z¯z¯ + zi = -i +1. Find the values of z.

Homework Equations

The Attempt at a Solution


Hi blckndglxy, welcome to PF.

You have to show some attempt at solving the problem. Write z as z=x+iy, substitute into the equation z¯z¯ + zi = -i +1 and solve.
 
  • Like
Likes   Reactions: Bibatshu Thapa
Bibatshu Thapa said:
Hey, I think z.z-=1 but what's with the zi thing. Can you upload the picture of your question? Its not clear enough.
You are not right, z.z- = |z|2, square of the magnitude of z. zi is z multiplied by i.
 
ehild said:
Hi blckndglxy, welcome to PF.

You have to show some attempt at solving the problem. Write z as z=x+iy, substitute into the equation z¯z¯ + zi = -i +1 and solve.
hello there.. so z¯ = x-iy right? so i have to replace the z¯ too right? sorry I'm still new and I'm clueless with this question..
 
blckndglxy said:
hello there.. so z¯ = x-iy right? so i have to replace the z¯ too right? sorry I'm still new and I'm clueless with this question..
Yes. Replace z with x+iy and z- with x-iy.
 
blckndglxy said:
hello there.. so z¯ = x-iy right? so i have to replace the z¯ too right? sorry I'm still new and I'm clueless with this question..
Writing ##z = x+iy## and ##bar{z} = x - iy##, your equation becomes
$$|z|^2 = 1 - i - zi$$.
Can you see how the value of ##x## can be determined right away from this equation? That leaves you with the simpler problem of finding ##y##.
 
Ray Vickson said:
Writing ##z = x+iy## and ##bar{z} = x - iy##, your equation becomes
$$|z|^2 = 1 - i - zi$$.
The original equation is z¯z¯ + zi = -i +1. z¯z¯ is not |z|2,
 
ehild said:
Hi blckndglxy, welcome to PF.

You have to show some attempt at solving the problem. Write z as z=x+iy, substitute into the equation z¯z¯ + zi = -i +1 and solve.
Thanks a lot. Well I had forgotten the fact you mentioned. Really HELPFUL!