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## Homework Statement

edit* It says Verify the formulas in problems

arcsin(z) = -iln(iz ±sqrt(1-z^2))

arccos(z) = iln(z ±sqrt(1-z^2))

tanh

^{-1}z = (1/2)ln((1+z)/(1-z))

## The Attempt at a Solution

yeah, my prof just threw it at us, all i have is nothing... absolutely nothing. I don't know why he does this to us.

The best i can think of is

z= sin(-iln(iz ±sqrt(1-z^2)))

z = (e

^{ln(iz ±sqrt(1-z^2))}+ e

^{-ln(iz ±sqrt(1-z^2))})/2i

((iz ±sqrt(1-z^2)) + (iz ±sqrt(1-z^2)

^{-1})/2i

but i doubt that is right