Complex numbers Simultaneos Eqn

[kukumaluboy]

Homework Statement

1) 2w+iz = 3; 2) (3-i)w - z = 1 +3i
2wi - z = 3i; 3w - iw - z = 1 + 3i

Substract (2) from (1):

2wi - z - (3w-iw-z) = 3i - (1+3i)
2wi -3w +iw = -1
3iw - 3w = -1
3w(i-1) = -1
3w = -1/(i-1) = -0.5i - 0.5
w = -i/6 - 1/6

But the answer is i/6 + 1/6 for W

 

[Ray Vickson]

Homework Statement

1) 2w+iz = 3; 2) (3-i)w - z = 1 +3i
2wi - z = 3i; 3w - iw - z = 1 + 3i

Substract (2) from (1):

2wi - z - (3w-iw-z) = 3i - (1+3i)
2wi -3w +iw = -1
3iw - 3w = -1
3w(i-1) = -1
3w = -1/(i-1) = -0.5i - 0.5
w = -i/6 - 1/6

But the answer is i/6 + 1/6 for W

$1/(i-1) = -(1/2)-(1/2)\,i$, so what is $-1/(i-1)$?

 

[kukumaluboy]

THANKS!
*That feeling when you admit the book is not wrong =/ *