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Complex numbers Simultaneos Eqn

  1. Nov 23, 2014 #1
    1. The problem statement, all variables and given/known data
    1) 2w+iz = 3; 2) (3-i)w - z = 1 +3i
    2wi - z = 3i; 3w - iw - z = 1 + 3i

    Substract (2) from (1):

    2wi - z - (3w-iw-z) = 3i - (1+3i)
    2wi -3w +iw = -1
    3iw - 3w = -1
    3w(i-1) = -1
    3w = -1/(i-1) = -0.5i - 0.5
    w = -i/6 - 1/6

    But the answer is i/6 + 1/6 for W
     
  2. jcsd
  3. Nov 23, 2014 #2

    Ray Vickson

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    ##1/(i-1) = -(1/2)-(1/2)\,i##, so what is ##-1/(i-1)##?
     
  4. Nov 23, 2014 #3
    THANKS!
    *That feeling when you admit the book is not wrong =/ *
     
    Last edited by a moderator: Nov 25, 2014
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