Complicated divisibility problem

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In summary, by considering divisibility by 5, we can determine the possible values of m^2 mod 5 to be 1, 4, or 0. Therefore, if none of m, n, or p are congruent to 0 mod 5, then m^2 + n^2 + p^2 cannot be divisible by 5.
  • #1
ripcity4545
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Homework Statement



If 5 divides m^2 + n^2 + p^2 , prove that 5 divides wither m, or n, or p.

Homework Equations



m,n,p are all integers

The Attempt at a Solution



I am having some major problems with this chapter on modular arithmetic. any help is much appreciated!

modular arithmetic is not needed to solve the problem, but may be helpful.
 
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  • #2
What possible values can m^2 have mod 5?
 
  • #3
Tedjn said:
What possible values can m^2 have mod 5?

Well if we are considering divisibility by 5, i can let
m=5k+r, where k is some integer and r may be 0, 1, 2, 3, or 4.

So m^2 = 25k^2 + 10kr +r^2
so
m^2 ≡ n mod 5 equals:

25k^2 + 10kr +r^2 ≡ n mod 5
and since 25k^2 + 10kr ≡ 0 mod 5, we are left with
r^2 ≡ n mod 5

so n may be 1, 4, or 0. Am I going in the right direction? Thanks for the reply.
 
  • #4
That's correct. So what can m^2 + n^2 + p^2 be if none are congruent to 0 mod 5?
 
  • #5
thanks for your help.
 
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1. What is a complicated divisibility problem?

A complicated divisibility problem is a mathematical question that involves dividing one number by another and determining if the quotient is a whole number without any remainder.

2. How do I solve a complicated divisibility problem?

To solve a complicated divisibility problem, you can use different strategies such as factoring, long division, or the divisibility rules for specific numbers. It is also helpful to break down the numbers into their prime factors.

3. What makes a divisibility problem complicated?

A divisibility problem can be considered complicated if the numbers involved are large or have multiple factors. It can also be complicated if the divisor is a larger number than the dividend.

4. Can a complicated divisibility problem have multiple solutions?

Yes, a complicated divisibility problem can have multiple solutions. This is because there can be more than one number that evenly divides into the dividend without leaving a remainder.

5. How can I check if my solution to a complicated divisibility problem is correct?

You can check your solution to a complicated divisibility problem by using the inverse operation, which would be multiplication. Multiply the quotient by the divisor and see if it equals the dividend. If it does, then your solution is correct.

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