Complicated divisibility problem

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Homework Help Overview

The problem involves proving that if 5 divides the sum of the squares of three integers m, n, and p, then at least one of those integers must also be divisible by 5. The subject area is modular arithmetic and divisibility.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss possible values of m^2 modulo 5 and explore the implications of these values on the overall sum. There is an examination of the form m = 5k + r and how it relates to the modular conditions.

Discussion Status

Some participants have provided insights into the modular properties of squares and have confirmed the correctness of certain approaches. The discussion is ongoing, with further exploration of the implications of the modular conditions on the sum of squares.

Contextual Notes

There is mention of potential confusion regarding the necessity of modular arithmetic for solving the problem, indicating varying levels of understanding among participants.

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Homework Statement



If 5 divides m^2 + n^2 + p^2 , prove that 5 divides wither m, or n, or p.

Homework Equations



m,n,p are all integers

The Attempt at a Solution



I am having some major problems with this chapter on modular arithmetic. any help is much appreciated!

modular arithmetic is not needed to solve the problem, but may be helpful.
 
Last edited:
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What possible values can m^2 have mod 5?
 
Tedjn said:
What possible values can m^2 have mod 5?

Well if we are considering divisibility by 5, i can let
m=5k+r, where k is some integer and r may be 0, 1, 2, 3, or 4.

So m^2 = 25k^2 + 10kr +r^2
so
m^2 ≡ n mod 5 equals:

25k^2 + 10kr +r^2 ≡ n mod 5
and since 25k^2 + 10kr ≡ 0 mod 5, we are left with
r^2 ≡ n mod 5

so n may be 1, 4, or 0. Am I going in the right direction? Thanks for the reply.
 
That's correct. So what can m^2 + n^2 + p^2 be if none are congruent to 0 mod 5?
 
thanks for your help.
 
Last edited:

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