- #1
ardentmed
- 158
- 0
Hey guys,
Few more questions for the problem set I've been working on. I'm doubting some of my answers and I'd appreciate some help.
Question:
The first one starts off easy but I found that it gets progress more challenging later on. So the rate of spread should be p'(t) which is:
p'(t) = 5/[e^.5t * (1+10e^(-.5t))^2]
As for 1b, I just used chain rule and product rule together to get:
f''(x) = 6xy'(x^2) + 4(x^3)g''(x^2)And finally, for the second question, if the tangent it horizontal, then dy/dx = 0, right?
Therefore, you solve for x, which leads you to:
sinx=-1
x=arcsin(-1)
x= -$\pi$/2
Which leads to ( -$\pi$/2 , 0 ) as the co-ordinates after substituting x = -$\pi$/2 into the original function.
Thanks in advance.
Few more questions for the problem set I've been working on. I'm doubting some of my answers and I'd appreciate some help.
Question:
The first one starts off easy but I found that it gets progress more challenging later on. So the rate of spread should be p'(t) which is:
p'(t) = 5/[e^.5t * (1+10e^(-.5t))^2]
As for 1b, I just used chain rule and product rule together to get:
f''(x) = 6xy'(x^2) + 4(x^3)g''(x^2)And finally, for the second question, if the tangent it horizontal, then dy/dx = 0, right?
Therefore, you solve for x, which leads you to:
sinx=-1
x=arcsin(-1)
x= -$\pi$/2
Which leads to ( -$\pi$/2 , 0 ) as the co-ordinates after substituting x = -$\pi$/2 into the original function.
Thanks in advance.