Compound shaft-axial force,internal force

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SUMMARY

The discussion focuses on the behavior of a compound solid shaft consisting of two different materials, A and B. When a force F is applied to one end of the shaft, the internal force in each member does not remain constant due to the differing material properties. Additionally, when torque is applied, the internal torque will differ between the two shafts, with the stiffer material bearing a greater load. The relationship between torsional stress and radius is defined by the formula τ = Tr/J, highlighting the impact of material stiffness on shear stress distribution.

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Mechanical engineers, materials scientists, and students studying mechanics of materials will benefit from this discussion, particularly those interested in the behavior of composite shafts under axial and torsional loads.

chandran
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There is a compound solid shaft. Outer shaft is made of material A and inner shaft is made of material B. One end of the shaft is fixed and another end has a force of F.

Will the internal force in each of the shaft members vary? why. If i pull with a force F, I think the internal force F will be same each of the solid members.

Similarly if a torque is applied at one end and the other end is fixed, will the internal torque differ in the two shafts
 
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The stiffer material will bear greater load.

In a compound shaft, the displacements of the different materials are equal.

In the case of a torque, the shear stresses will also be different. For one, the torsional stress at radius r is given by,

\tau\,=\,\frac{Tr}{J}

where T is applied Torque, r is radius and J is torsional moment of inertia.
 

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