Compressed Spring Between Two Boxes

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    Compressed Spring
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Homework Help Overview

The problem involves two blocks of different masses on a frictionless surface, separated by a compressed spring. Upon release, the blocks move, and the question focuses on determining the velocity of the center of mass of the system after the spring is released.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the center of mass and the movement of the blocks, with some drawing parallels to explosive events. There are attempts to apply conservation of linear momentum to the scenario, and questions arise about the relevant equations for the center of mass.

Discussion Status

The discussion is ongoing, with participants exploring the implications of conservation of momentum and the concept of center of mass. Some guidance has been offered regarding the use of equations related to the center of mass, but no consensus has been reached on the correct interpretation or application of these concepts.

Contextual Notes

There is a noted uncertainty regarding the specific equations for the center of mass and how they apply to this problem. Participants are also navigating the implications of the initial conditions and the nature of the system's motion.

Soniteflash
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Homework Statement


Two blocks of masses M and 2M are on a frictionless horizontal surface and are held in place with a compressed spring of negligible mass between them. If the blocks are then released and the block of mass 2M leaves the spring with a velocity v, the velocity of the center of mass of the blocks is

A zero
B -(v/2)
C -(2v/3)
D -(3v/2)
E -2v

Homework Equations


n/a ?

The Attempt at a Solution


I do not understand how the center of mass relates to the movement of the blocks. I remember from class that if an object exploded into thousands of pieces the center of mass would still be at the original position.
So I assume it is A. Zero.
 
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Soniteflash said:
I do not understand how the center of mass relates to the movement of the blocks. I remember from class that if an object exploded into thousands of pieces the center of mass would still be at the original position.
So I assume it is A. Zero.

Can you explain why it would be zero? I mean, you are right. But it might be beneficial to examine the problem a little more deeply.
 
AlephNumbers said:
Can you explain why it would be zero? I mean, you are right. But it might be beneficial to examine the problem a little more deeply.
I am not quite sure but I thought it is similar or identical sort of to an explosion.
 
It is very similar to an explosion. Try using conservation of linear momentum and the equation for the velocity of the center of mass of a system of particles (or blocks, in this case) to show why your answer is correct.
 
For linear momentum :
Pi=Pf
0 = m(-2v) + (2mv)
0 = -2mv + 2mv
0 = 0
Linear momentum is conserved.

Hmm, I don't really know an equation for the velocity of the center of mass of a system of particles. I know that the velocities of the boxes are both in opposite directions.
 
It isn't too difficult to prove.

Start with the equation for the center of mass of a system of particles. If you don't know that either, you can find it here http://hyperphysics.phy-astr.gsu.edu/hbase/cm.html.

Any ideas on what you can do to this equation to create an equation for the velocity of the center of mass?
It involves calculus.
 

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