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**Homework Statement**

An

*m*= 1.3 kg block and an

*M*= 3.0 kg block have a spring compressed between them and rest on a frictionless table. With a stopper in place that prevents

*m*from moving, the spring is compressed and released so that

*M*moves away with a speed 2.0 m/s.

The spring is compressed exactly as before, but this time without the stopper in place. Both blocks are released at the same time. What is the speed of mass

*m*when the spring stops acting on it?

**The attempt at a solution**

What I did to solve this was I used the equation v

_{fM}= 2v

_{CM}- v

_{0M}

v

_{CM}= (Mv

_{0M}+ mv

_{0m})/(m+M)

Then I said Mv

_{0M}= mv

_{fm}+ Mv

_{fM}

So, (Mv

_{0M}- Mv

_{fM})/m = v

_{fm}

I got the final answer to be 1.79 m/s, but it is wrong. Thanks for helping.