- #1
Raj Kishore
- 6
- 0
Homework Statement
An m = 1.3 kg block and an M = 3.0 kg block have a spring compressed between them and rest on a frictionless table. With a stopper in place that prevents m from moving, the spring is compressed and released so that M moves away with a speed 2.0 m/s.
The spring is compressed exactly as before, but this time without the stopper in place. Both blocks are released at the same time. What is the speed of mass m when the spring stops acting on it?
The attempt at a solution
What I did to solve this was I used the equation vfM = 2vCM - v0M
vCM = (Mv0M + mv0m)/(m+M)
Then I said Mv0M = mvfm + MvfM
So, (Mv0M - MvfM)/m = vfm
I got the final answer to be 1.79 m/s, but it is wrong. Thanks for helping.
An m = 1.3 kg block and an M = 3.0 kg block have a spring compressed between them and rest on a frictionless table. With a stopper in place that prevents m from moving, the spring is compressed and released so that M moves away with a speed 2.0 m/s.
The spring is compressed exactly as before, but this time without the stopper in place. Both blocks are released at the same time. What is the speed of mass m when the spring stops acting on it?
The attempt at a solution
What I did to solve this was I used the equation vfM = 2vCM - v0M
vCM = (Mv0M + mv0m)/(m+M)
Then I said Mv0M = mvfm + MvfM
So, (Mv0M - MvfM)/m = vfm
I got the final answer to be 1.79 m/s, but it is wrong. Thanks for helping.