Compton Effect, frequency question

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SUMMARY

The discussion centers on calculating the frequency of a deflected X-ray after it interacts with a thin piece of metal, using the Compton Effect. The initial frequency of the X-ray is 3.74 x 1020 Hz, and the deflection angle is 48°. The calculations involve using the equations Δλ = (h/mc)(1 - cosθ) and E = hf, leading to a final frequency of approximately 6.27 x 10-19 Hz for the deflected X-ray. Participants clarified the use of radians in calculations, which affected the results.

PREREQUISITES
  • Understanding of the Compton Effect and its equations
  • Familiarity with Planck's constant (h = 6.63 x 10-34 Js)
  • Knowledge of the relationship between energy, frequency, and wavelength (E = hf and λ = c/f)
  • Basic proficiency in trigonometry, specifically cosine functions
NEXT STEPS
  • Study the derivation and applications of the Compton Effect in quantum mechanics
  • Learn how to convert between radians and degrees in trigonometric calculations
  • Explore the implications of X-ray frequency changes in medical imaging
  • Investigate the role of electromagnetic radiation in various scientific fields
USEFUL FOR

Students in physics, particularly those studying quantum mechanics, as well as professionals in medical imaging and radiation physics will benefit from this discussion.

Kennedy111
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Homework Statement


An X-ray with a frequency of 3.74 x 10^20 Hz is incident on a thin piece of metal. The lower frequency X ray on the other side is observed deflected at 48°. What is the frequency fo the deflected X ray?

fi = 3.74 x 10^20 Hz
Deflected at 48°


Homework Equations


I'm not sure... I would guess..

Δλ= (h/mc)(1-cosθ)
E = hf
E = hc/λ
(hc/λ)=hf

The Attempt at a Solution


I really have no idea where to begin... If someone could just start me off that would be awesome :) This is my attempt anyway..

Ei = hf
= (6.63 x 10^-34 Js)(3.74 x 10^20 Hz)
= 2.47962 x 10^-13 J

E = hc/λ
λ= hc/E
= (6.63 x 10^-34 js)(3.00 x 10^8 m/s) / (2.47962 x 10^-13 J)
= 8.02139037 x 10^-13 m

Δλ = λf - λi
λf = Δλ + λi
= ((6.63 x 10^-34 Js) / (9.11 x 10^-31 kg)(3.00 x 10^8 m/s))(1- cos48) + 8.02139037 x 10^-13 m
=4.78097437 x 10^-12 m

Ef = hc/λ
=(6.63 x 10^-34 Js)(3.00 x 10^8 m/s) / (4.78097437 x 10^-12 m)
=4.16023983 x 10^-14 J

E = hf
f = E/h
= (4.16023983 x 10^-14 J) / (6.63 x 10^-34 Js)
= 6.274871536 x 10^-19 Hz

Yeah... I don't think this is right..

Please help!
 
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Kennedy111 said:
Ei = hf
= (6.63 x 10^-34 Js)(3.74 x 10^20 Hz)
= 2.47962 x 10^-13 J

E = hc/λ
λ= hc/E
= (6.63 x 10^-34 js)(3.00 x 10^8 m/s) / (2.47962 x 10^-13 J)
= 8.02139037 x 10^-13 m
x-rays are electromagnetic radiation. So, the easiest way to get back and forth between λ and f is to use the basic wave relation c = λf. Thus, λ = c/f. You can check that this will give the same result for λi.
Δλ = λf - λi
λf = Δλ + λi
= ((6.63 x 10^-34 Js) / (9.11 x 10^-31 kg)(3.00 x 10^8 m/s))(1- cos48) + 8.02139037 x 10^-13 m
=4.78097437 x 10^-12 m
Looks set up correctly, but I don't get the same value for λf.
Ef = hc/λ
=(6.63 x 10^-34 Js)(3.00 x 10^8 m/s) / (4.78097437 x 10^-12 m)
=4.16023983 x 10^-14 J

E = hf
f = E/h
= (4.16023983 x 10^-14 J) / (6.63 x 10^-34 Js)
= 6.274871536 x 10^-19 Hz

Again, you can just use f = c/λ.
 
Wait... was your λf value 1.06771397 x 10^-12 ??

My calculator was in radian mode...
 
Kennedy111 said:
Wait... was your λf value 1.06771397 x 10^-12 ??

My calculator was in radian mode...

I get about 1.605 x 10^-12 m
 
Hmm... I'm not sure what I'm doing wrong then...
 
Nevermind! I got it now! :D Thanks :)
 

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