Compute area using divergence and flux?

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The discussion focuses on computing the area enclosed by the curve defined by the parametric equations g(t) = a cos³(t), a sin³(t) for t in the interval [0, 2π]. The user has successfully derived the unit tangent and outward normal vectors but seeks guidance on calculating the area without a specified vector field F. The solution involves applying Green's Theorem, which relates the line integral around a simple closed curve to a double integral over the plane region bounded by the curve. By selecting M(x,y) = x and L(x,y) = 0, the area can be computed effectively.

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Compute area using divergence and flux??

Consider the curve given by g(t) =acos^3(t),asin^3(t), where t is [0; 2pi] and a > 0 is a constant.

(a) Find the unit tangent and outward normal vectors.
(b) Compute the area enclosed by this curve.

I have done part a), and I know that
flux of F = divergence x area
but for part b), i m not given a vector field F. so how am I suppose to approach this question and possibly find the divergence (thus the area)? any hint or solution would be much appreciated. ^__^
 
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Since this is in the plane, it is simpler to use Green's theorem rather than the divergence theorem.

Green's theorem says that
\oint (Ldx+ Mdy)= \int\int \left(\frac{\partial M}{\partial x}- \frac{\partial L}{\partial y}\right) dA

The integral on the right will be the area as long as
\frac{\partial M}{\partial x}- \frac{\partial L}{\partial y}= 1

One such choice is M(x,y)= x, L(x,y)= 0.
 

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