Compute Flux of Vector Field Through Surface S

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SUMMARY

The discussion focuses on computing the flux of the vector field \(\vec{F} = 3xi + yj + zk\) through the surface defined by the equation \(z + 4x + 2y = 12\) in the first octant. The correct approach involves determining the surface function \(f(x,y) = 12 - 4x - 2y\) and calculating the dot product with the normal vector \(\langle -f_x, -f_y, 1 \rangle\), which results in \(\langle 4, 2, 1 \rangle\). The integral to solve is \(\int (8x + 12) \, dx \, dy\), with the correct bounds derived from the triangular region formed by the intersections of the surface with the axes, specifically \(0 < x < 3\) and \(0 < y < 6 - 2x\).

PREREQUISITES
  • Vector calculus, specifically surface integrals
  • Understanding of dot products in three-dimensional space
  • Knowledge of how to determine bounds for double integrals
  • Familiarity with the concept of flux through a surface
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  • Study the method for calculating surface integrals in vector calculus
  • Learn how to derive bounds for double integrals from geometric shapes
  • Explore the application of the Divergence Theorem in vector field analysis
  • Practice problems involving flux calculations through various surfaces
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Students and professionals in mathematics, physics, and engineering who are working on vector calculus problems, particularly those involving surface integrals and flux calculations.

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Homework Statement



Compute the flux of the vector field, , through the surface, S.
[tex]\vec{F}[/tex]= 3xi + yj + zk and S is the part of the surface z + 4x + 2y = 12 in the first octant oriented upward.

Homework Equations


by definition from my book the integral is
[tex]\int[/tex]F(x,y,f(x,y)[tex]\circ[/tex]<-fx,fy,1>dxdy

for a plane oriented up

The Attempt at a Solution



So to get f(x,y) from the surface i did
z=f(x,y)=12-4x-2y

I have to find the integral of the vector field dot product with <-fx,-fy,1> which turns out to be <4,2,1>

So <3x,y,12-4x-2y>dot<4,2,1>=8x+12

Next I have to find
[tex]\int[/tex]8x+12dxdy

I'm not sure what to set my values at to solve this, I tried 0<x<3 and 0<y<6
With those values my integral equaled 288 which was the wrong answer
then I tried to dot the first part with <-4,-2,1> and my answer was -432 which was still wrong

Can someone help me find the integration values for the first octant of that plane, I think that's all I need to solve this?
 
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The xy domain is a triangle, it's bounded by x=0, y=0 and the line 0=12-4x-2y, isn't it? 0<x<3 and 0<y<6 is a rectangle.
 

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